KOH is the limiting reagent
The molar ratio is 1:2
So if you have 6 moles of MgCl2 you need 12 moles of KOH
Answer:
Nitrogen molecule (N2)
The electronic configuration of nitrogen (Z=7) = 1s2 2s2 2px12py12pz1.
The total number of electrons present in the nitrogen molecule (N2) is 14.
In order to maximize energy, these 14 electrons can be accommodated in the different molecular orbitals.
N2: KK'(σ2s)2 (σ*2s)2 (π2Px)2 (π2py)2 (σ2pz)2
Here (σ1s)2 (σ*1s)2 part of the configuration is abbreviated as KK’, which denotes the K shells of the two atoms. In calculating bond order, we can ignore KK’, as it includes two bonding and two antibonding electrons.
The bond order of N2can be calculated as follows:
Here, Nb = 10 and Na = 4
Bond order = (Nb−Na) /2
B.O = (10−4)/2
B.O = 3
So your answer should be C3.
L'air n'est pas un mélange gazeux, donc la réponse serait le verre
Answer:
Explanation:
Hello!
In this case, since the by-mass percent of a solution is a measure of the mass of the solute over the mass of the solution:
As we know the mass of the solution and the by-mass percent, we can compute the mass of glucose in the 480 g of solution:
Thus, by plugging in the data, we obtain:
Finally, since the solution is made up of glucose and water, we compute the mass of water as follows:
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