Answer:
The less mass in a given volume of air the less dense the air is going to be.
Stoichiometry <span>of the reaction:
</span><span>2 KClO</span>₃<span> = 2 KCl + 3 O</span>₂
↓ ↓
2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?
KClO₃ = 2 * 3 / 2
KClO₃ = 6 / 2
= 3 moles de KClO₃
hope this helps!
Answer:
water
Explanation:
because the others are in compounds and can not be considered as products lonely.
Because when the cells divide (resulting in more cells) the multicellular organism mantains its strong cells and when one cell is damaged the other cells compensate for that damaged cell.
Answer:
3853 g
Step-by-step explanation:
M_r: 107.87
16Ag + S₈ ⟶ 8Ag₂S; ΔH°f = -31.8 kJ·mol⁻¹
1. Calculate the moles of Ag₂S
Moles of Ag₂S = 567.9 kJ × 1 mol Ag₂S/31.8kJ = 17.858 mol Ag₂S
2. Calculate the moles of Ag
Moles of Ag = 17.86 mol Ag₂S × (16 mol Ag/8 mol Ag₂S) = 35.717 mol Ag
3. Calculate the mass of Ag
Mass of g = 35.717 mol Ag × (107.87 g Ag/1 mol Ag) = 3853 g Ag
You must react 3853 g of Ag to produce 567.9 kJ of heat
