Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Add all the sides together
10+15+7+8+8+2=50 ft
Answer:
it is the surface of the 3d shape spread out like an blue print
Step-by-step explanation:
The two angles form a straight line and need to equal 180 when added together:
7x + 28 + 33 = 180
Simplify:
7x + 61 = 180
Subtract 61 from both sides
7x = 119
Divide both sides by 7
X = 17
Answer: B.17
