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VLD [36.1K]
3 years ago
6

Consider the reaction co(g)+nh3(g)âhconh2(g), kc=0.900 if a reaction vessel initially contains only co and nh3 at concentrations

of 1.00 m and 2.00 m, respectively, what will the concentration of hconh2 be at equilibrium? express your answer with the appropriate units.
Chemistry
2 answers:
Murrr4er [49]3 years ago
6 0
The answer is 254 units 

Cerrena [4.2K]3 years ago
5 0

Answer:

See explanation below

Explanation:

Let's write the equilibrium reaction:

CO(g) + NH3(g) <------> HCONH2(g)   Kc = 0.9

We know the initial concentrations which are 1 and 2 M. In order to know the concentration of equilibrium, we need to do an ICE chart, and then, write the equilibrium expression for this reaction to calculate the concentration.

The ICE chart:

       CO(g) + NH3(g) <------> HCONH2(g)   Kc = 0.9

i)        1              2                         0

c)       -x           -x                          x

e)      1-x          2-x                        x

The equilibrium expression:

Kc = [HCONH2] / [CO][NH3]

Replacing the values we have:

0.9 = x / (1-x)(2-x)

0.9(1-x)(2-x) = x

0.9(x²-3x+2) = x

0.9x² - 2.7x + 1.8 = x

0.9x² - 3.7x + 1.8 = 0

From here, we solve for x using the general formula for a quadratic expression:

x = -b ±√b² - 4ac / 2a

Replacing the values here:

x = 3.7 ±√(3.7)² - 4 * 0.9 * 1.8 / 2*0.9

x = 3.7 ±√13.69 - 6.48 / 1.8

x = 3.7 ± 2.69 / 1.8

x1 = 3.7 - 2.69 / 1.8 = 0.56

x2 = 3.7 + 2.69 / 1.8 = 3.55

As 3.55 is > 1 and 2 from the initial concentrations, the correct value is x1 therefore:

[HCONH2] = 0.56 M

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1 year ago
What mass of dinitrogen monoxide, N2O, contains the same number of molecules as 3.00 g of trichlorofluoromethane, CCl3F?
erica [24]

Answer:

0.9612 g

Explanation:

First we <u>calculate how many moles are there in 3.00 g of CCl₃F</u>, using its <em>molar mass</em>:

  • 3.00 g CCl₃F ÷ 137.37 g/mol = 0.0218 mol CCl₃F

Now, we need to calculate how many grams of N₂O would have that same number of molecules, or in other words, <em>the same amount of moles</em>.

Thus we <u>calculate how many grams would 0.0218 moles of N₂O weigh</u>, using the <em>molar mass of N₂O</em> :

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3 0
3 years ago
How many grams of As2S3 are in 3.25 moles?
laiz [17]

Answer:

Explanation:

Molar mass of As2S3= {75(2) + 32(3)}

= 150 + 96 = 246g/mol

Amount = 3.25mole

And

Amount = mass/ molar mass

mass = amount × molar mass

Mass = 3.25 × 246

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6 0
4 years ago
If 12.6 grams of iron (III) oxide reacts with 9.65 grams of carbon monoxide to produce 7.23 g of pure iron, what are the theoret
Mariana [72]
The balanced equation is Fe₂O₃ + 3 CO = 2 Fe + 3 CO₂.
Next step is to convert everything to moles.
12.6g Fe₂O₃ x (1 mol Fe₂O₃ / 159.7g Fe₂O₃) = 0.07890 mol Fe₂O₃ 
9.65g CO x (1 mol CO / 28.01g CO) = 0.3445 mol CO
The third step is to determine the limiting and excess reactants.
0.07890 mol Fe₂O₃ x (3 mol CO/1 mol Fe₂O₃) = 0.2367 mol CO
Therefore Fe₂O₃ is the limiting reagent while CO is in excess.

0.07890 mol Fe x (2 mol Fe(s) / 1 mol Fe₂O₃) = 0.1578 mol Fe(s) 
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%yield = (7.23g / 8.812g) x 100% = 82.0% is the percent yield
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3 years ago
......................................................
Diano4ka-milaya [45]

Answer:

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