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Alina [70]
3 years ago
7

How many grams of As2S3 are in 3.25 moles?

Chemistry
1 answer:
laiz [17]3 years ago
6 0

Answer:

Explanation:

Molar mass of As2S3= {75(2) + 32(3)}

= 150 + 96 = 246g/mol

Amount = 3.25mole

And

Amount = mass/ molar mass

mass = amount × molar mass

Mass = 3.25 × 246

mass = 799.5g

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HELP! What is the percent composition of carbon in caffeine (C₈H₁₀N₄O₂)? Show your work
Dominik [7]

Caffeine has the following percent composition: carbon 49.48%, hydrogen 5.19%, oxygen 16.48% and nitrogen 28.85%. Its molecular weight is 194.19 g/mol.

8 0
3 years ago
Carbon-14 has a half-life of 5,700 years.
Maksim231197 [3]

Answer:

3.106\ \text{g}

Explanation:

t_{1/2} = Half-life of carbon = 5700 years

t = Time at which the remaining mass is to be found = 10400 years

m_0 = Initial mass of carbon = 11 g

Decay constant is given by

\lambda=\dfrac{\ln2}{t_{1/2}}

Amount of mass remaining is given by

m=m_0e^{-\lambda t}\\\Rightarrow m=m_0e^{-\dfrac{\ln2}{t_{1/2}} t}\\\Rightarrow m=11e^{-\dfrac{\ln 2}{5700}\times 10400}\\\Rightarrow m=3.106\ \text{g}

The amount of the substance that remains after 10400 years is 3.106\ \text{g}.

5 0
3 years ago
What must be true about two objects if heat is flowing between them?
Katarina [22]

Answer:

The temperatures of the objects must be different

Explanation:

if heat is flowing between two objects, then the objects must be at different temperatures.

7 0
3 years ago
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Can sugar and water be separated using distillation?
Bogdan [553]

Answer:

Yes.

Explanation:

Because distillation separates substances based on their different boiling points.

8 0
3 years ago
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Please need this ASAP. Calculate the mass of lime, CaO, that would be produced from 250 tonnes of limestone,
stiv31 [10]

Answer:

1.4×10⁸ g of CaO

Explanation:

We'll begin by converting 250 tonnes to grams (g). This can be obtained as follow:

1 tonne = 1×10⁶ g

Therefore,

250 tonne = 250 × 1×10⁶

250 tonne = 2.5×10⁸ g

Next, the balanced equation for the reaction.

CaCO₃ —> CaO + CO₂

Next, we shall determine the mass of CaCO₃ that decomposed and the mass CaO produced from the balanced equation. This can be obtained as follow:

Molar mass of CaCO₃ = 40 + 12 + (16×3)

= 40 + 12 + 48

= 100 g/mol

Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g

Molar mass of CaO = 40 + 16

= 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

SUMMARY:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Finally, we shall determine the mass of CaO produced by the decomposition of 250 tonnes (i.e 2.5×10⁸ g) of CaCO₃. This can be obtained as follow:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Therefore, 2.5×10⁸ g of CaCO₃ will decompose to produce =

(2.5×10⁸ × 56)/100 = 1.4×10⁸ g of CaO.

Thus, 1.4×10⁸ g of CaO will be obtained from 250 tonnes (i.e 2.5×10⁸ g) of CaCO₃.

6 0
3 years ago
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