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tatuchka [14]
3 years ago
11

Find the length of MT for which MATH is a parallelogram

Mathematics
2 answers:
maks197457 [2]3 years ago
7 0

since f=4 and 4+2=6 and 6x2=12

so the answer is D. 12

Anit [1.1K]3 years ago
5 0
AP and PH are congruent. Thus we can set up and equation: 2f - 5 = 5f - 17 and solve for f. We see that f = 4. MP and PT are congruent. So we set up another equation: f + 2 = g and substitute 4 in for f. g = 6 and we can then finish the equation from before and find MT = 12.
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Identify the digit with the given place value in number 173.514 hundredths
Llana [10]

Answer: We are given the number 173.514

Each of the digits in this number has the following place value:

\begin{gathered} 1\rightarrow\text{ Hundreds} \\ 7\rightarrow\text{ Tens} \\ 3\rightarrow\text{ Ones} \\ \text{.}\rightarrow\text{  Decimal Point} \\ 5\rightarrow\text{ Tenth} \\ 1\rightarrow\text{  Hundreth} \\ 4\rightarrow\text{  Thousandth} \end{gathered}

Secondly, We have to identify the numbers in digit 185.712

\begin{gathered} 1\rightarrow\text{ Thousand} \\ 8\rightarrow\text{ Hundred} \\ 5\rightarrow\text{ Tens} \\ \text{. Decimal point} \\ 7\text{ }\rightarrow\text{Thenth} \\ 1\rightarrow\text{ Hundreth} \\ 2\text{ }\rightarrow\text{ Thousandth} \\  \end{gathered}

5 0
1 year ago
Triangle abc is such that ab=4 and ac=8 if m is the midpoint of bc and am=3, what is the length of bc?
zavuch27 [327]
This is an interesting question. I chose to tackle it using the Law of Cosines.
  AC² = AB² + BC² - 2·AB·BC·cos(B)
  AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
  AC² - 2·AM² = -AB² + BC² - 2·MB²

We know that MB = BC/2. When we substitute the given information, we have
  8² - 2·3² = -4² + BC² - BC²/2
  124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
  2√31 = BC ≈ 11.1355

4 0
4 years ago
The parabola opens upward has x = 2 as an axis of symmetry and contains the non -vertex points (1, 9) and (4, 27) write the equa
Sedaia [141]

Answer:

<h3>               f(x) = 6(x - 2)² + 3</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k    - vertex form of the equation of the parabola with vertex (h, k)

"the parabola opens upward" means:  a>0

"the parabola has x = 2 as an axis of symmetry" means:  h = 2

so f(x) = a(x - 2)² + k

"the parabola contains the point (1, 9)" means:

9 = a(1 - 2)² + k

9 = a(-1)² + k

9 = a + k

k = 9 - a

"the parabola contains the point (4, 27)" means:

27 = a(4 - 2)² + k

so:

27 = a(2)² + 9 - a

27 = 4a + 9 - a

3a = 18

a = 6

and  k = 9 - 6 = 3

Therefore the vertex form for this parabola is:

                                     <u> f(x) = 6(x - 2)² + 3</u>

4 0
3 years ago
A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
Gnom [1K]

Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0
3 years ago
3/4 of Ana's books are equal to two-thirds of Jake's books find the ratio of the number of Ana's books it to the number of Jake'
dimaraw [331]
First you want to change the fractions to the same denominator 
3/4 = 9/12 and 2/3 = 8/12
then you put it in ratio form...
the answer is 9:8
8 0
3 years ago
Read 2 more answers
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