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3 years ago

Circuit that has only one path for the current to follow

Physics

1 answer:

Vadim26 [7]3 years ago

4 0

Answer:

Series circuit

Explanation:

The type of circuit can be divided into series and parallel. In the series circuit, there is only one loop/path. If the path is cut or stopped, the current of the circuit will be stopped completely. A parallel circuit has more than one loops. This means the circuit has alternative paths that it can travel in case that one path is blocked or cut. This alternative path makes the parallel circuit have a lower resistance compared to the series.

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Answer:

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3 years ago

Find the intensity of a 55 dB sound given I 0=10^-12W/m^2

MakcuM [25]

Answer:

3.16 × $10^{-7}$ W/ $m^{2}$

Explanation:

β(dB)=10 × $log_{10}(\frac{I}{I_{0} })$

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Therefore plugging into the equation the values,

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3 years ago

Use the fact that 1inch=2.54cm and convert 52 inches into the equivalent length in centimeters.

Lelu [443]

Answer:

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2 years ago

Find electric field at point p which is a distance l away from the both +q and -q

denis-greek [22]

Answer:

$\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

$=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }$

Where

q is the charge
r is the distance
$E$ is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1 $=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }$

F2 $=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

⇒

F1+F2= $\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

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3 years ago

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