Answer:
ω₁ = 8 rad/s
Explanation:
Assuming
1) the clay sticks to the disc we can apply conservation of angular momentum
2) That the disc moment of inertia is 1.5 kg•m²
Initial angular momentum = L = I₀ω₀ = 1.5(14) = 21 kg•m²/s
After the clay joins the party, the moment of inertia is
I₁ = 1.5 + 0.5(1.5²) = 2.625 kg•m²
21 = 2.625ω₁
ω₁ = 8 rad/s
The magnitude of maximum magnetic force that could be exerted on the proton is 1.44 x 10^-12 N.
The magnitude of the force on a charged particle moving in a magnetic field is given by the formula,
F= qvB
Here q is the charge on proton = 1.6 x 10^-19 C.
v is the velocity with which the particle is moving = 6.00 x 10^6 m/s
And B is the value of the magnetic field = 1.5 T
Putting the given values in the above equation,
F = 1.6 x 10^-19 x 6 x 10^6 x 1.5 = 1.44 x 10^-12 N.
Hence, the magnitude of maximum magnetic force that could be exerted on the proton is 1.44 x 10^-12 N.
To know more about "magnetic force", refer to the link given below:
brainly.com/question/13791875?referrer=searchResults
#SPJ4
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
Sea scorpions or Eurypterids lived about 251.9 million years ago. They were formidable predators and hunters, but they were wiped out in the Great Permian Mass Extinction, which is also known as the Great Dying (96% of all species on Earth went extinct).The largest species like Jaekelopterus was over 7 feet long! They were mainly thought to go extinct because of a slew of natural disasters that occurred when a comet hit the Earth, as well as increased volcanic activity polluting the seas that Sea scorpions lived in, as well as rising sea temperatures. The Silurian, when these Sea scorpions proliferated was when the water was cooler, holding in more nutrients, allowing both Sea Scorpions and other animals to spread all over the world. But as the oceans became polluted from the volcanoes (and the ash they produced) and the global ocean temperatures began to rise, many animals may not have been able to cope or adapt to the extreme change, becoming helpless in their nutrient deficient water (compared to what they were used to).
I hope this helps!
Answer:
Final Length = 30 cm
Explanation:
The relationship between the force applied on a string and its stretching length, within the elastic limit, is given by Hooke's Law:
F = kΔx
where,
F = Force applied
k = spring constant
Δx = change in length of spring
First, we find the spring constant of the spring. For this purpose, we have the following data:
F = 50 N
Δx = change in length = 25 cm - 20 cm = 5 cm = 0.05 m
Therefore,
50 N = k(0.05 m)
k = 50 N/0.05 m
k = 1000 N/m
Now, we find the change in its length for F = 100 N:
100 N = (1000 N/m)Δx
Δx = (100 N)/(1000 N/m)
Δx = 0.1 m = 10 cm
but,
Δx = Final Length - Initial Length
10 cm = Final Length - 20 cm
Final Length = 10 cm + 20 cm
<u>Final Length = 30 cm</u>