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Aleks [24]
3 years ago
8

Can u help me please

Physics
1 answer:
DanielleElmas [232]3 years ago
5 0

Answer:

Find answer below.

Explanation:

a. Group 2: alkaline earth metals. Some examples of alkaline earth metals are magnesium, calcium, barium, etc.

b. Transition metals: metals with unpredictable properties.

c. Chlorine: halogen.

d. Metalloid: make good semiconductors.

e. Group 1: alkali metals. These includes the soft, light and reactive chemical elements found in group 1 of the periodic table. Some examples are hydrogen, potassium, lithium, sodium, etc.

f. Noble gases: has a full outer energy level (shell). These are chemical elements with eight valence electrons and as such have a full octet. Some examples are argon, neon, etc.

h. Metal: loses electron in bonding. They usually lose electrons in order to attain a full outer energy level or noble gas electronic configuration.

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(a) 0.345 T

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Solution:

As per the question:

Hall emf, V_{Hall} = 20\ mV = 0.02\ V

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Hall emf, V'_{Hall} = 69\ mV = 0.069\ V

Now,

Drift velocity, v_{d} = \frac{V_{Hall}}{B}

v_{d} = \frac{0.02}{0.10} = 0.2\ m/s

Now, the expression for the electric field is given by:

E_{Hall} = Bv_{d}sin\theta                            (1)

And

E_{Hall} = V_{Hall}d

Thus eqn (1) becomes

V_{Hall}d = dBv_{d}sin\theta

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d = distance

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(a) When \theta = 90^{\circ}

B = \frac{0.069}{0.2\times sin90} = 0.345\ T

(b) When \theta = 60^{\circ}

B = \frac{0.069}{0.2\times sin60} = 0.398\ T

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