Answer:
The net force acting on this object is 180.89 N.
Explanation:
Given that,
Mass = 3.00 kg
Coordinate of position of 
Coordinate of position of 
Time = 2.00 s
We need to calculate the acceleration
For x coordinates
On differentiate w.r.to t
On differentiate again w.r.to t
The acceleration in x axis at 2 sec
For y coordinates
On differentiate w.r.to t
On differentiate again w.r.to t
The acceleration in y axis at 2 sec
The acceleration is
We need to calculate the net force
The magnitude of the force
Hence, The net force acting on this object is 180.89 N.
Answer:
Explanation:
a. WEIGHT: As we have seen, weight is the gravitational force exerted on an object by the Earth (or any other celestial body). If an object is near the Earth's surface and has mass, then the object has a weight. The magnitude of its weight is w = mg and its direction is toward the center of the Earth.
Answer:
The size of the force developing inside the steel rod is 32039.28 N
Explanation:
Given;
length of the steel rod, L = 1.55 m
cross sectional area of the steel, A = 4.89 cm²
temperature change, ∆T = 28.0 K
coefficient of linear expansion for steel, α = 1.17 × 10⁻⁵ 1/K
Young modulus of steel, E = 200.0 GPa.
Extension of the steel is given as;
α ∆T L = FL / AE
α ∆T = F/AE
F = AEα ∆T
F = ( 4.89 x 10⁻⁴)(200 x 10⁹)(1.17 × 10⁻⁵)(28.0 K)
F = 32039.28 N
Therefore, the size of the force developing inside the steel rod when its temperature is raised, is 32039.28 N
The correct option is D.
Because <span>the distance that the honey flows is a dependent variable. Becuase the coefficient of viscosity is dependent on the velocity gradient (v/L). And, </span>Viscosity is very temperature dependent • It decreases with increasing temperature (in case of liquids). But, Viscosity of a gas increases with increasing temperature.
