Answer:- Ca = +2, S = +6 and O = -2
Solution:- There are certain rules for oxidation numbers. As per the rule, oxidation number of alkaline earth metals in their compounds is +2.
Oxidation number of oxygen in it's compounds is -2(except peroxides) and the sum of oxidation numbers of all the elements of a neutral compound is zero.
Since, Ca is +2 and O is -2, the oxidation number of S could easily be calculated for the given compound as:
Let's say the oxidation number of S in 
is 
. Let's make the algebraic equation and solve it.
Hence. the oxidation number of Ca is +2, O is -2 and S is +6.
<span>1. </span>To solve this we assume
that the gas is an ideal gas. Then, we can use the ideal gas equation which is
expressed as PV = nRT. At a constant temperature and number of moles of the gas
the product of PV is equal to some constant. At another set of condition of
temperature, the constant is still the same. Calculations are as follows:
P1V1 =P2V2
V2 = P1 x V1 / P2
V2 = 203 x 40.0 / 35.0
V2 =232 L
The answer is 2) 4.7 g/mL because the solid use 17 mL and 80g/17mL is 4,7 g/mL.
The correct answer is Period B. Exponential growth is an increase in size at a constantly growing rate. Period A appears to be linear growth, Period C is no growth at all and Period D is exponential decline.
I believe the answer is b
