Answer:
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Explanation:
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To solve this problem we will apply the concepts related to real power in 3 phases, which is defined as the product between the phase voltage, the phase current and the power factor (Specifically given by the cosine of the phase angle). First we will find the phase voltage from the given voltage and proceed to find the current by clearing it from the previously mentioned formula. Our values are
Real power in 3 phase
Now the Phase Voltage is,
The current phase would be,
Rearranging,
Replacing,
Therefore the current per phase is 2.26kA
Answer:
a) 116.67 MPa
b) 368.85 GPa
c) -1.0122 *10^{-4}
Explanation:
Given data:
length of bar is 1.50 m
total elongation in bar = 1.22 mm
axial load = 35.0 kN
cross section dimension = 6 by 50 mm
proportional limit = 300 MPa
a) AXIAL STRESS
Stress =force/area
b) modulus of elasticity
where E = modulus of elasticity
E = 36.8.85 GPa
c)
where is poisson's ration= 0.32