Answer:
a) 23.89 < -25.84 Ω
b) 31.38 < 25.84 A
c) 0.9323 leading
Explanation:
A) Calculate the load Impedance
current on load side = 0.75 p.u
power factor angle = 25.84
= 0.75 < 25.84°
attached below is the remaining part of the solution
<u>B) Find the input current on the primary side in real units </u>
load current in primary = 31.38 < 25.84 A
<u>C) find the input power factor </u>
power factor = 0.9323 leading
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<em>attached below is the detailed solution </em>
Answer:
R= 1.25
Explanation:
As given the local heat transfer,

But we know as well that,

Replacing the values

Reynolds number is define as,

Where V is the velocity of the fluid and \upsilon is the Kinematic viscosity
Then replacing we have



<em>*Note that A is just a 'summary' of all of that constat there.</em>
<em>That is
</em>
Therefore at x=L the local convection heat transfer coefficient is

Definen that we need to find the average convection heat transfer coefficient in the entire plate lenght, so

The ratio of the average heat transfer coefficient over the entire plate to the local convection heat transfer coefficient is

Answer:
F=531831381
Explanation:
There are two ways of doing this question:
1) By Formula
2) By Using Compound interest Table
By Formula:

Where:
F is future value
A is annual amount per year
i is interest rate
n is number of years

F=531831381
By Using Compound interest Table:
F=A(F/A,i,n)
From Table F/A at i=8% and n=8 is 10.6366
F=50000000*(10.6366)
F=531830000≅531831381
The difference in two answers is due to decimal points if you take value from table to greater decimal points you will get the exact answer as by using formula.
Answer:
a, c
Explanation:
As the problem statement tells you, the phasor technique cannot be used when the frequencies are different. The frequencies are different when the coefficients of t are different. The different ones are highlighted.
a. 45 sin(2500t – 50°) + 20 cos(1500t +20°)
b. 25 cos(50t + 160°) + 15 cos(50t +70°)
c. 100 cos(500t +40°) + 50 sin(500t – 120°) – 120 cos(500t + 60°) -100 sin(10,000t +90°) + 40 sin(10, 100t – 80°) + 80 cos(10,000t)
d. 75 cos(8t+40°) + 75 sin(8t+10°) – 75 cos(8t + 160°)