Answer:
284.4 m/s
Explanation:
At the inlet of the nozzle P =1 atm.
Temperature T = 250° C
Velocity of the steam at the inlet V_1 = 30 m/s
Change in enthalpy Δh = 40 KJ/kg
let V_2 be the final velocity
then
![V_2 =\sqrt{2\Delta h+V_1^2} \\=\sqrt{2\times40+30^2}\\= 284.4 m/s](https://tex.z-dn.net/?f=V_2%20%3D%5Csqrt%7B2%5CDelta%20h%2BV_1%5E2%7D%20%5C%5C%3D%5Csqrt%7B2%5Ctimes40%2B30%5E2%7D%5C%5C%3D%20284.4%20m%2Fs)
Answer:
unmanned is a plane without a flyer in other words a drone. The sound can effect its use or people near by hurting the hairs that transport sound in the ears. The effect it has on itself is that after putting out sound the drone that runs on battery power can give out and crash somewhere can that sound can make people no longer hear, because i didn't really know what you were asking please tell me and i can give you a better answer
Explanation:
They all share the way that they are fundamentally designed: if they are quite complex, they will share the same basic logic foundations, like the way that the programming languages work. They also all share the method of construction and common and fundamental electronic components, like resistors, capacitors and transistors. As we humans design them, they make logical sense to at least someone, and probably only discounting the internet, you can probably draw logic diagrams and whatever to represent how they work.
Because they are designed by Humans, in a way they all mimic how our brains and society work. Also, as yet there are no truly intelligent technological systems, and are only able to react to a situation how they have been programmed to do so.
Answer: The exit temperature of the gas in deg C is
.
Explanation:
The given data is as follows.
= 1000 J/kg K, R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)
= 100 kPa, ![V_{1} = 15 m^{3}/s](https://tex.z-dn.net/?f=V_%7B1%7D%20%3D%2015%20m%5E%7B3%7D%2Fs)
![T_{1} = 27^{o}C = (27 + 273) K = 300 K](https://tex.z-dn.net/?f=T_%7B1%7D%20%3D%2027%5E%7Bo%7DC%20%3D%20%2827%20%2B%20273%29%20K%20%3D%20300%20K)
We know that for an ideal gas the mass flow rate will be calculated as follows.
![P_{1}V_{1} = mRT_{1}](https://tex.z-dn.net/?f=P_%7B1%7DV_%7B1%7D%20%3D%20mRT_%7B1%7D)
or, m = ![\frac{P_{1}V_{1}}{RT_{1}}](https://tex.z-dn.net/?f=%5Cfrac%7BP_%7B1%7DV_%7B1%7D%7D%7BRT_%7B1%7D%7D)
=
= 10 kg/s
Now, according to the steady flow energy equation:
![mh_{1} + Q = mh_{2} + W](https://tex.z-dn.net/?f=mh_%7B1%7D%20%2B%20Q%20%3D%20mh_%7B2%7D%20%2B%20W)
![h_{1} + \frac{Q}{m} = h_{2} + \frac{W}{m}](https://tex.z-dn.net/?f=h_%7B1%7D%20%2B%20%5Cfrac%7BQ%7D%7Bm%7D%20%3D%20h_%7B2%7D%20%2B%20%5Cfrac%7BW%7D%7Bm%7D)
![C_{p}T_{1} - \frac{80}{10} = C_{p}T_{2} - \frac{130}{10}](https://tex.z-dn.net/?f=C_%7Bp%7DT_%7B1%7D%20-%20%5Cfrac%7B80%7D%7B10%7D%20%3D%20C_%7Bp%7DT_%7B2%7D%20-%20%5Cfrac%7B130%7D%7B10%7D)
![(T_{2} - T_{1})C_{p} = \frac{130 - 80}{10}](https://tex.z-dn.net/?f=%28T_%7B2%7D%20-%20T_%7B1%7D%29C_%7Bp%7D%20%3D%20%5Cfrac%7B130%20-%2080%7D%7B10%7D)
= 5 K
= 5 K + 300 K
= 305 K
= (305 K - 273 K)
= ![32^{o}C](https://tex.z-dn.net/?f=32%5E%7Bo%7DC)
Therefore, we can conclude that the exit temperature of the gas in deg C is
.
Yes unless it is a green arrow. Then you have the right away.