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3 years ago

5 kg of a wet steam has a volume of 2 m3

Engineering

1 answer:

Verizon [17]3 years ago

4 0

Have you seen the state of her body. Mad. If I wear it I ain’t wearing a jolly. ADEOLA wanna ride in the gysa

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Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 76 vol% carbide

Georgia [21]

Answer:

The answer is below

Explanation:

Given that:

Volume of carbide ( $V_{C}$ ) = 76% = 0.76, Volume of Nickel ( $V_{M}$ ) = 100% - 76% = 24% = 0.24, thermal conductivities of carbide ( $E_{C}$ ) = 30 W/m-K and thermal conductivities of meta. ( $E_M$ ) = 67 W/m-K

a) The maximum thermal conductivity is given by:

Max = $E_CV_c+E_mV_m=(0.76*30) + (0.24*67) = 38.88\ W/mK$

b) The minimum thermal conductivity is given by:

Min = $\frac{E_ME_C}{E_MV_C+E_CV_M}=\frac{30*67}{(0.76*67)+(0.24*30)}=34.58\ W/mK$

8 0

3 years ago

The Environmental Protection Agency (EPA) has standards and regulations that says that the lead level in soil cannot exceed the

DENIUS [597]

Answer:

See below

Explanation:

Check One-Sample T-Interval Conditions

Random Sample? √

Sample Size ≥30? √

Independent? √

Population Standard Deviation Unknown? √

One-Sample T-Interval Information

Formula --> $CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})$
Sample Mean --> $\bar{x}=390.25$
Critical Value --> $t^*=2.0096$ (given $df=n-1=50-1=49$ degrees of freedom at a 95% confidence level)
Sample Size --> $n=50$
Sample Standard Deviation --> $S_x=30.5$

Problem 1

The critical t-value, as mentioned previously, would be $t^*=2.0096$ , making the 95% confidence interval equal to $CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})=390.25\pm2.0096(\frac{30.5}{\sqrt{50}})\approx\{381.5819,398.9181\}$

This interval suggests that we are 95% confident that the true mean levels of lead in soil are between 381.5819 and 398.9181 parts per million (ppm), which satisfies the EPA's regulated maximum of 400 ppm.

3 0

2 years ago

A bar of 75 mm diameter is reduced to 73mm by a cutting tool while cutting orthogonally. If the mean length of the cut chip is 7

barxatty [35]

Answer:

r=0.31

Ф=18.03°

Explanation:

Given that

Diameter of bar before cutting = 75 mm

Diameter of bar after cutting = 73 mm

Mean diameter of bar d= (75+73)/2=74 mm

Mean length of uncut chip = πd

Mean length of uncut chip = π x 74 =232.45 mm

So cutting ratio r

$Cutting\ ratio=\dfrac{Mean\ length\ of cut\ chip}{Mean\ length\ of uncut\ chip}$

$r=\dfrac{73.5}{232.45}$

r=0.31

So the cutting ratio is 0.31.

As we know that shear angle given as

$tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }$

Now by putting the values

$tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }$

$tan\phi =\dfrac{0.31cos15 }{1-0.31sin15 }$ \

Ф=18.03°

So the shear angle is 18.03°.

4 0

4 years ago

Researchers at the University of__________modified the iPhone to allow it to create medical images.

Morgarella [4.7K]

Answer:

Explanation:

I'm so sorry if this is wrong. This is what I think it is though, I had a class like this and I think this is what I said.

3 0

3 years ago

Read 2 more answers

For RTK to work, what do we need besides two or more receivers collecting data from a sufficient number of satellites simultaneo

Liula [17]

Answer:

phase measurement and the information content

Explanation:

The full form of RTK is Real Time Kinematic. It is used for satellite navigation technique to increase the precision of the position data that is derived from the positioning systems based on satellites like the NavIC, GPS, Galileo, BeiDou and GLONASS. It takes help of the measurements of phase of signal's carrier wave and also the information content of these signals and it also relies on the single interpolated virtual station in order to provide the real time corrections and provide correct and accurate information.

7 0

3 years ago