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rodikova [14]
3 years ago
5

The marking off table has a mass of 500kg.

Engineering
1 answer:
d1i1m1o1n [39]3 years ago
5 0

Answer:

0.1336

Explanation:

The formula for pressure is force exerted by the object divided by area the object covers.

The marking off table has a mass of 500 kg. You can find its weight by applying the equation;

w= m* g where w is weight , m is mass and g is acceleration due to gravity

w= 500 * 9.81

w= 4905 N

Formula for pressure is;

P= F/A

3.5 *100000 N = 4905 / A

350000 N = 4905 /A

A= 4905/350000

A= 0.0140 m²

To get the internal diameter apply the formula;

A=πr²  where A is area of a cylindrical shaped object, r is radius

0.0140 = π * r²

0.0140/π = r²

0.0044608 = r²

√0.0044608 = r

0.06678 m = r ------D = 2r

0.1336 = D

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The rate of flow through an ideal clarifier is 8000m3 /d, the detention time is 1h and the depth is 3m. If a full-length movable
Fittoniya [83]

Answer:

a) 35%

b) yes it can be improved by moving the tray near the top

   Tray should be located ( 1 to 2 meters below surface )

   max removal efficiency ≈ 70%

c) The maximum removal will drop as the particle settling velocity = 0.5 m/h

Explanation:

Given data:

flow rate = 8000 m^3/d

Detention time = 1h

depth = 3m

Full length movable horizontal tray :  1m below surface

<u>a) Determine percent removal of particles having a settling velocity of 1m/h</u>

velocity of critical sized particle to be removed = Depth / Detention time

= 3 / 1 = 3m/h

The percent removal of particles having a settling velocity of 1m/h ≈ 35%

<u>b) Determine if  the removal efficiency of the clarifier can be improved by moving the tray, the location of the tray  and the maximum removal efficiency</u>

The tray should be located near the top of the tray ( i.e. 1 to 2 meters below surface ) because here the removal efficiency above the tray will be 100% but since the tank is quite small hence the

Total Maximum removal efficiency

=  percent removal_{above} + percent removal_{below}

= ( d_{a},v_{p} ) . \frac{d_{a} }{depth}  + ( d_{a},v_{p} ) . \frac{depth - d_{a} }{depth}  = 100

hence max removal efficiency ≈ 70%

<u>c) what is the effect of moving the tray would be if the particle settling velocity were equal to 0.5m/h?</u>

The maximum removal will drop as the particle settling velocity = 0.5 m/h

7 0
3 years ago
What is the first thing to do when you make a three-point turn?.
Jlenok [28]

Answer:

1. Move as far right as possible, check traffic, and signal a left turn.

2. Turn the steering wheel sharply to the left and move forward slowly.

3. Shift to reverse, turn your wheels sharply to the right, check traffic, and back your vehicle to the right curb, or edge of roadway.

5 0
3 years ago
1. A gas pressure difference is applied to the legs of a U-tube manometer filled with a liquid with S = 1.5. The manometer readi
julia-pushkina [17]

Answer:

1) The pressure difference is 4.207 kilopascals.

2) 2.5 pounds per square inch equals 5.093 inches of mercury and 5.768 feet of water.

Explanation:

1) We can calculate the gas pressure difference from the U-tube manometer by using the following hydrostatic formula:

\Delta P = \frac{S\cdot \rho_{w}\cdot g \cdot \Delta h}{1000} (Eq. 1)

Where:

S - Relative density, dimensionless.

\rho_{w} - Density of water, measured in kilograms per cubic meter.

g - Gravitational acceleration, measured in meters per square second.

\Delta h - Height difference in the U-tube manometer, measured in meters.

\Delta P - Gas pressure difference, measured in kilopascals.

If we know that S = 1.5, \rho_{w} = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}} and \Delta h = 0.286\,m, then the pressure difference is:

\Delta P = \frac{1.5\cdot \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.286\,m)}{1000}

\Delta P = 4.207\,kPa

The pressure difference is 4.207 kilopascals.

2) From Physics we remember that a pound per square unit equals 2.036 inches of mercury and 2.307 feet of water and we must multiply the given pressure by corresponding conversion unit: (p = 2.5\,psi)

p = 2.5\,psi\times 2.037\,\frac{in\,Hg}{psi}

p = 5.093\,in\,Hg

p = 2.5\,psi\times 2.307\,\frac{ft\,H_{2}O}{psi}

p = 5.768\,ft\,H_{2}O

2.5 pounds per square inch equals 5.093 inches of mercury and 5.768 feet of water.

4 0
4 years ago
A sewer pipe 8 inches in diameter can carry 0.662 ft3/s when flowing at a depth of 4 inches.
Rom4ik [11]

Answer:

a) the flow under full capacity is  q₂= 1.334 ft³/s

b) the velocity would be v= 3.793 ft/s

Explanation:

a) Since the pipe has 8 inches in diameter but 4 are covered with water flow ( half of a circle in area=A₁) , q₁=0.662 ft³/s then

q₁=A₁*v

then for the same velocity v but area A₂=2*A₁

flow under full capacity= q₂ = A₂*v= 2*A₁*v= 2*q₁=2*0.662 ft³/s= 1.334 ft³/s

b) when flowing at a depth of 4 inches

A₁= (1/2)*(π*D²/4) = π* (1/8)*(8 in)² = 8π in² * (1  ft²/ 144  in²) = π/18 ft² = 0.1745 ft²

then

v=q₁/A₁ = 0.662 ft³/s/0.1745 ft²= 3.793 ft/s

v= 3.793 ft/s

6 0
4 years ago
Pie charts should have no more than eight segments. True or False?
Pepsi [2]

Answer:

Explanation:

Pie charts generally should have no more than eight segments.

6 0
3 years ago
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