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3 years ago

What are the components of a vector with a magnitude of 4.00 and a direction of -112 degrees

Physics

1 answer:

irakobra [83]3 years ago

3 0

Apply the equation. to find the magnitude, which is 1.4.

Apply the equation theta = tan–1(y/x) to find the angle: tan–1(1.0/–1.0) = –45 degrees. However, note that the angle must really be between 90 degrees and 180 degrees because the first vector component is negative and the second is positive.

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An airplane with constant speed 696 mph than another 40 minutes constant speed 804 mph what is distance it go?

sleet_krkn [62]

Answer:

536 miles

Explanation:

If the airplane is running at a speed of 804 miles per hour, and covers a distance, x in a particular number of mile. The distance in mile can be gotten they the application of direct formula. Multiplying the speed by the time it took, and thus

804 mph * 40

Remember the time is in minutes and not hours, so, you convert it to hours.

804 * 40/60 hours =

536 miles

6 0

3 years ago

A cylinder with a piston contains 0.200 mol of oxygen at 2.00×105 Pa and 360 K . The oxygen may be treated as an ideal gas. The

ikadub [295]

Answer:

A. $W=600\ J$

B. $Q=2112\ J$

C. $\Delta U=1512\ J$

D. $W=0\ J$

Explanation:

Given:

no. of moles of oxygen in the cylinder, $n=0.2$

initial pressure in the cylinder, $P_i=2\times 10^5\ Pa$

initial temperature of the gas in the cylinder, $T_i=360\ K$

According to the question the final volume becomes twice of the initial volume.

Using ideal gas law:

$P.V=n.R.T$

$2\times 10^5\times V_i=0.2\times 8.314\times 360$

$V_i=0.003\ m^3$

Work done by the gas during the initial isobaric expansion:

$W=P.dV$

$W=P_i\times (V_f-V_i)$

$W=2\times 10^5\times (0.006-0.003)$

$W=600\ J$

we have the specific heat capacity of oxygen at constant pressure as:

$c_v=21\ J.mol^{-1}.K^{-1}$

Now we apply Charles Law:

$\frac{V_i}{T_i} =\frac{V_f}{T_f}$

$\frac{0.003}{360} =\frac{0.006}{T_f}$

$T_f=720\ K$

Now change in internal energy:

$\Delta U=n.c_p.(T_f-T_i)$

$\Delta U=0.2\times 21\times (720-360)$

$\Delta U=1512\ J$

Now heat added to the system:

$Q=W+\Delta U$

$Q=600+1512$

$Q=2112\ J$

Since during final cooling the process is isochoric (i.e. the volume does not changes). So,

$W=0\ J$

7 0

3 years ago

It is known that the population mean for the verbal section of the SAT is 500 with a standard deviation of 100. In 2006, a sampl

kvasek [131]

Answer

given,

SAT is 500 with a standard deviation of 100.

a sample of 400 students whose family income was between $70,000 and $80,000 had an average verbal SAT score of 511.

sample mean = $\dfrac{standard\ deviation}{\sqrt{n}}$

= $\dfrac{100}{\sqrt{400}}$

= 5

95% confidence level is achieved within +/- 1.960 standard deviations.

1.960 standard deviations x 5 is equal to +/- 9.8

confidence interval = 511 - 9.8 --- 511 + 9.8

= 501.2-----520.8

4 0

2 years ago

A bag of groceries has a weight of 44 newtons. Find its approximate weight in kilograms.

Artist 52 [7]

You cannot convert newtons to kilograms, or pounds to kilograms,
or kilograms to pounds or newtons.

Newtons and pounds are units of FORCE. Kilogram is a unit of MASS.

If an object weighs 44 newtons on Mars,
then its mass is about 13.5 kilograms

If an object weighs 44 newtons on the Moon,
then its mass is about 27.2 kilograms.

If an object weighs 44 newtons on Earth,
then its mass is about 4.5 kilograms.

4 0

3 years ago

Prove that relation between S.I unit of energy and commercial unit of energy

Oduvanchick [21]

Relation between SI unit and Commercial Unit of energy is 1 kWh = 3.6 × 10^6 J

Explanation:

Commercial unit of energy is kiloWatt-hour (kWh) and SI unit of energy is Joule (J).
1 kiloWatt hour = 1000W × 1h

Now, 1 W = 1 J/sec

⇒ 1 kiloWatt hour = 1000 × 60 × 60 (Since 1 h = 60 × 60 s)

⇒ 1 kWh = 3.6 × 10^6 J

5 0

3 years ago