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Verizon [17]
3 years ago
5

How can coaches improve team performance?

Physics
2 answers:
yan [13]3 years ago
7 0

Answer:

by giving guides and help the team improve as one

Explanation:

uysha [10]3 years ago
4 0

Answer:

Coaches plan, conduct, and evaluate the team on a regular basis. They are the leaders of the team, so they help motivate the players. They are able to communicate with the athletes and determine the best learning styles for each player.

Explanation:

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The built-up beam is formed by welding together the thin plates of thickness 5 mm. determine the location of the shear center o.
atroni [7]

Answer:

The location of the shear center o is 0.033 or 33 m

Explanation:

Solution

Recall that,

The moment of inertia of the section is =  I = 0.05 * 0.4 ^3 /12 + 0.005 * 0.2 ^3/12

= 30 * 10 ^ ⁻⁶ m⁴

Now,

The first moment of inertia is

Q =ῩA = [ (0.1 -x) + x/2] (0.005 * x)

= 0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²

Thus,

The shear flow is,

q =  VQ/I

so,

P =  (0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²)/ 30 * 10 ^⁻⁶

P = (16.67 x - 83. 33  x²)

The shear force resisted by the shorter web becomes

Vw,₂ = 2∫ = ₀.₁ and ₀ = P (16.67 x - 83. 33  x²) dx = 0.11x

Then,

We take the moment at a point A

∑Mₐ = 0

- ( p * e)- (Vw₂ * 0.3 ) = 0

e =  0.11 p * 0.3/p

which gives us 0.033 m

= 33 m

Therefore the location of the shear center o is 0.033 or 33 m

Note: Kindly find an attached diagram to the question given above as part of the explanation solved with it.

4 0
3 years ago
PLEASE HELP: Which of the following procedures describes how you could best test the hypothesis that a crumpled piece of paper f
Mariulka [41]

Answer:

A because it is the most affective way to do it

Explanation:

7 0
4 years ago
Magnetic fields are produced by: atoms currents voltages charges
baherus [9]
The answer is currents
3 0
4 years ago
A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s .
zimovet [89]

Answer:

Force exerted, F = 1.5 N

Explanation:

It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.

i.e. u = 0

v = 30 m/s

Time taken, t = 0.06 s

Mass of the paper, m = 0.003 kg

We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :

F=m\times a

F=m\times (\dfrac{v-u}{t})

F=0.003\times (\dfrac{30}{0.06})

F = 1.5 N

So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.

6 0
3 years ago
A.to reduce<br> b.to dispose<br> c.to prevent<br> d.to help
kenny6666 [7]

Answer:

to prevent cuz now for my mind when you prevent it it will not happen to you or nothing happened to you

5 0
3 years ago
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