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Ipatiy [6.2K]
3 years ago
11

A 12.41 g sample of nabr contains 22.34% na by mass. considering the law of constant composition (definite proportions) how many

grams of sodium does a 8.99 g sample of sodium bromide contain?
Chemistry
2 answers:
scZoUnD [109]3 years ago
7 0

Answer:

m_{Na}=2.01g

Explanation:

Hello,

In this case, given the by mass percent of sodium in sodium bromide::

\% Na=\frac{m_{Na}}{m_{NaBr}}*100\%=22.34  \%

Solving for the mass of sodium, considering the constant composition of sodium in the sodium bromide, we obtain:

m_{Na}=\frac{\% Na*m_{NaBr}}{100\%} =\frac{22.34\%*8.99g}{100\%} \\\\m_{Na}=2.01g

Best regards.

Helga [31]3 years ago
6 0
I'm assuming you mean how many grams of sodium does 8.99 grams of sodium bromide have, because Bromine would not have any sodium in it.

Then, just direct calculate 22.34
(22.34 \div 100) \times 8.99 = 2.008366
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