This graph shows how the total length Kimi has knit depends on the number of nights she has spent knitting.

const2013 [10]

Answer:

B. p+121 is ≤ 345

Step-by-step explanation:

Talula can't go over the amount of 345 because it would go over the limit therefore the less than or equal to sign is needed. It would be p PLUS 121 because it would be a number less than or equal to 345 and p is the variable that is has to be less than or equal to 345.

7 0

3 years ago

How do i decompose the number 740

Paladinen [302]

Lets do this.

so when you decompose 740 you first get

700

and then you get

40

so your numbers are

700 and 40

or

7 hundreds, 4 tens

3 0

3 years ago

Read 2 more answers

(HURRY! I'M BEING TIMED)Write the partial fraction decomposition of the rational expression.

Aleonysh [2.5K]

Answer:

The partial fraction decomposition is $\frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}$ .

Step-by-step explanation:

Partial-fraction decomposition is the process of starting with the simplified answer and taking it back apart, of "decomposing" the final expression into its initial polynomial fractions.

To find the partial fraction decomposition of $\frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}$ :

First, the form of the partial fraction decomposition is

$\frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{A}{x + 1}+\frac{B}{\left(x + 1\right)^{2}}+\frac{C}{x + 2}$

Write the right-hand side as a single fraction:

$\frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B}{\left(x + 1\right)^{2} \left(x + 2\right)}$

The denominators are equal, so we require the equality of the numerators:

$- 4 x^{2} + 13 x - 12=\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B$

Expand the right-hand side:

$- 4 x^{2} + 13 x - 12=x^{2} A + x^{2} C + 3 x A + x B + 2 x C + 2 A + 2 B + C$

The coefficients near the like terms should be equal, so the following system is obtained:

$\begin{cases} A + C = -4\\3 A + B + 2 C = 13\\2 A + 2 B + C = -12 \end{cases}$

Solving this system, we get that $A=50, B=-29, C=-54$ .

Therefore,

$\frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}$

7 0

3 years ago

ken paid $12 for two magazines. The cost of each magazine was a multiple of $3. What are the possible prices of the magazines?

Harlamova29_29 [7]

<span>The possible price of the magazine can be either $ 9 , $ 6 , or $3 First we need to understand the different between a cost and a price. A cost is the amount of money needed to Produce the magazine, while a price is the amount of money that the sellers get when he hand it over to customer since its said the cost is in multiple of $ 3 , the possible price of two magazine would be : $ 9 + $3 = $ 12 $6 + $6 = $ 12 $3 + $ 9 = $ 12</span>

6 0

3 years ago

Perform the indicated operation 3 1/2 - 1 7/10

Vilka [71]

Answer: 1 4/5

Step-by-step explanation:

3 5/10 - 1 7/10 = 1 8/10

1 8/10 = 1 4/5

7 0

2 years ago