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Klio2033 [76]
4 years ago
6

This graph shows how the total length Kimi has knit depends on the number of nights she has spent knitting.

Mathematics
1 answer:
andriy [413]4 years ago
4 0

Answer 2 centimeters per night

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Can the sides of a triangle have sides of 5, 8, and 16 ???
Nata [24]

Answer:

No.

Step-by-step explanation:

The triangle inequality theorem states that the sum of two sides of a triangle must be greater than the third side.

5 + 8 = 13.

13, which is the sum of two sides, is not larger than 16, the third side.

Therefore, a triangle cannot have these side lengths.

4 0
3 years ago
Name:<br>Solve each abso<br>1)<br>-13 + 1 - 2 + 51 – 6​
slavikrds [6]
I believe that answer is 31
7 0
4 years ago
What is the solution to 2 6/7 divided by 2/14
Black_prince [1.1K]
The answer is 10 i believe 
4 0
3 years ago
Read 2 more answers
A student researcher compares the ages of cars owned by students and cars owned by faculty at a local state college. A sample of
diamong [38]

Answer:

The point estimate for the true difference between the population means is 0.13.

The 90% confidence interval for the difference between the true mean ages for cars owned by students and faculty is between -0.35 years and 0.61 years.

Step-by-step explanation:

To solve this question, before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When we subtract two normal variables, the mean is the subtraction of the means while the standard deviation is the square root of the sum of the variances.

A sample of 263 cars owned by students had an average age of 7.25 years. The population standard deviation for cars owned by students is 3.77 years.

This means that:

\mu_s = 7.25, \sigma_s = 3.77, n = 263, s_s = \frac{3.77}{\sqrt{263}} = 0.2325

A sample of 291 cars owned by faculty had an average age of 7.12 years. The population standard deviation for cars owned by faculty is 2.99 years.

This means that:

\mu_f = 7.12, \sigma_f = 2.99, n = 291, s_f = \frac{2.99}{\sqrt{291}} = 0.1753

Difference between the true mean ages for cars owned by students and faculty.

Distribution s - f. So

\mu = \mu_s - \mu_f = 7.25 - 7.12 = 0.13

This is also the point estimate for the true difference between the population means.

s = \sqrt{s_s^2+s_f^2} = \sqrt{0.2325^2+0.1753^2} = 0.2912

90% confidence interval for the difference:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = zs = 1.645*0.2912 = 0.48

The lower end of the interval is the sample mean subtracted by M. So it is 0.13 - 0.48 = -0.35 years

The upper end of the interval is the sample mean added to M. So it is 0.13 + 0.48 = 0.61 years.

The 90% confidence interval for the difference between the true mean ages for cars owned by students and faculty is between -0.35 years and 0.61 years.

5 0
3 years ago
Terri wrote the system of linear inequalities
Eddi Din [679]

Question: Terri wrote the system of linear inequalities.

-3x - 3y > -18

-X<-y

Select all of the ordered pairs that are part of the solution set for this system of linear inequalities.

A: (-1,5)

B: (2, 4)

C: (3, 3)

D: (4.6)

E: (5,2)

Answer: A,b,d

3 0
3 years ago
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