An object traveling at a 5.0 m/s east has a mass of 4.0 kg. what is the magnitude of the object’s momentum?

Physics

2 answers:

Nezavi [6.7K]3 years ago

6 0

Answer:

Object's momentum, p = 20 kg-m/s

Explanation:

It is given that,

Mass of the object, m = 4 kg

Velocity of the object, v = 5 m/s

We need to find the object's momentum. It is given by ;

p = m × v

$p=4\ kg\times 5\ m/s$

p = 20 kg-m/s

So, the momentum of the object is 20 kg-m/s. Hence, this is the required solution.

inysia [295]3 years ago

4 0

Mass = 4.0 kg
velocity= 5.0 m/s

momentum= mass × velocity= 4.0 × 5.0 = 20.0 kg m/s

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You're driving down the highway late one night at 20 m/s when a deer steps onto the road 44 m in front of you. Your reaction tim

never [62]

Answer:

14.0 m

25.1 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Distance traveled in the reaction time

Distance = Speed × Time

$\text{Distance}=20\times 0.5=10\ m$

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-20^2}{2\times -10}\\\Rightarrow s=20\ m$

Distance in which the car will stop is 10+20 = 30.0 m

So, the car will not hit the deer

Distance between the car and deer is 44-30 = 14.0 m

$\text{Distance}=u\times 0.5=0.5u\ m$

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u^2=v^2-2as\\\Rightarrow u^2=0^2-2\times -10\times (44-0.5u)\\\Rightarrow u^2=20(44-0.5u)\\\Rightarrow u^2=880-10u\\\Rightarrow u^2+10u-880=0$

$u=\frac{-10+\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}, u=\frac{-10-\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}\\\Rightarrow u=25.08, -35.08\ m/s$