All categories

3 years ago

Find the distance between the points given. (3, 4) and (4, 7) √(10) 3 2√2

Mathematics

1 answer:

Tom [10]3 years ago

5 0

Answer:

Step-by-step explanation:

givens

x1 = 3

x2 = 4

y1 = 4

y2 = 7

formula

d = sqrt( (x1 - x2)^2 + (y1 - y2)^2 )

solution

d = sqrt( (3 - 4)^2 + (4 - 7)^2 )

d = sqrt ( 1 + 3^2)

d = sqrt( 1 + 9)

d = sqrt( 10)

You might be interested in

What does this description reveal about Lucia

GrogVix [38]

Answer:

it's the answer A

Step-by-step explanation:

becAuse she is scared / nerv

5 0

3 years ago

Read 2 more answers

I NEED HELP IN THIS QUESTION PLEASE

aliina [53]

Looks like you got it right :) Each package contains 8 chocolates, so to find 8 containers, just multiply by 8 to get 64, which would be H.

5 0

2 years ago

Hello My name es Liliana y arigato bye

alexandr402 [8]

Answer:

?????.... hii erica herrrr

6 0

2 years ago

Read 2 more answers

Simplify 1/3(1/2-1/3)-1/3(1/3-1/2)

zhuklara [117]

Answer:

im pretty sure its 1/9

Step-by-step explanation:

1/3 x 1/6-1/3 x (-1/6)

1/18 + 1/18

5 0

2 years ago

Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu

Softa [21]

Answer-

The polynomial function is,

$y=x^4-10x^3+38x^2-64x+40$

Solution-

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

$\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))$ ( ∵ (3-i) is the conjugate of (3+i) )

$\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)$

$\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)$

$\Rightarrow y=(x^2-4x+4)(x^2-6x+10)$

$\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10$

$\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40$

$\Rightarrow y=x^4-10x^3+38x^2-64x+40$

Therefore, this is the required polynomial function.

4 0

3 years ago