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Kruka [31]
4 years ago
15

a moving company is called into a building and asked to relocate 520 bricks to a location 15 meters above the ground. if each br

ick is 4 kilograms,what amount of work will be needed to accomplish the task?(a)305,760J(b)203,840J(c)229,320J(d)588,000J
Physics
2 answers:
Monica [59]4 years ago
6 0

I just took the test, A. 305,760 J good luck

Triss [41]4 years ago
4 0

Work = (force) x (height)

         = (mass x gravity) x (height)


         (520 bricks) x (4 kg/brick) x (9.8 m/s²) x (15 meters)

     =  (520 x 4 x 9.8 x 15)    kg-m²/s²

     =      305,760  (kg-m/s²) (m)

     =      305,760    Newton - meter

     =      305,760 Joules    (choice-'a')
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Earth receives some of the Sun's energy in the form of heat and light.
musickatia [10]

Answer:

a) nuclear

Explanation:

8 0
3 years ago
If a train is travelling 200km/hour eastward for 1800 seconds how far does it travel?
Olenka [21]

Answer:

Distance, d = 99990 meters

Explanation:

It is given that,

Speed of the train, v = 200 km/h = 55.55 m/s

Time taken, t = 1800 s

Let d is the distance covered by the train. We know that the speed of an object is given by total distance covered divided by total time taken. Mathematically, it is given by :

v=\dfrac{d}{t}

d=v\times t

d=55.55\times 1800

d = 99990 m

So, the distance covered by the train is 99990 meters. Hence, this is the required solution.

5 0
3 years ago
Consider the circuit shown in the figure to find the power delivered to 6 Ohm resistance (in W). Given that Vs= 30
vekshin1

66.7 Watts

Explanation:

Let R_{1}=1.0 ohms, R_{2}=3.0ohms and R_{3}=6.0\:ohms. Since R_{2} and R_{3} are in parallel, their combined resistance R_{23} is given by

\dfrac{1}{R_{23}}=\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}

or

R_{23}=\dfrac{R_{2}R_{3}}{R_{2}+ R_{3}}=2.0\:ohms

The total current flowing through the circuit <em>I</em> is given

I=\dfrac{V_{s}}{R_{Total}}

where

R_{Total}=R_{1}+R_{23}= 3.0\:ohms

Therefore, the total current through the circuit is

I=\dfrac{30\:V}{3.0\:ohms}=10\:A

In order to find the voltage drop across the 6-ohm resistor, we first need to find the voltage drop across the 1-ohm resistor V_{1}:

V_{1}=(10\:A)(1.0\:ohms)=10\:V

This means that voltage drop across the 6-ohm resistor V_{3} is 20 V. The power dissipated <em>P</em> by the 6-ohm resitor is given by

P=I^{2}R_{3}= \dfrac{V^{2}}{R_{3}}=\dfrac{(20\:V)^{2}}{6\:ohms}= 66.7 W

4 0
3 years ago
A 2000 kg truck is traveling at 5 m/s and collides with a 1000 kg car that is not moving. After the collision, the 2000 truck st
sp2606 [1]

Answer:

A) 10 m/s

Explanation:

We know that according to conservation of momentum,

m1v1 + m2v2 = m1u1 + m2u2  ..............(equation 1)

where m1 and m2 are masses of two bodies, v1 and v2 are initial velocity before collision and u1 and u2 are final velocities after collision respectively.

From the given data

If truck and car are two bodies

truck :       m1 = 2000 Kg           v1 = 5 m/s                u1 = 0

car    :        m2 = 1000 kg           v2 = 0                      u2 = ?

final velocity of truck and initial velocity of car are static because the objects were at rest in the respective time.

substituting the values in equation 1, we get

(2000 x 5) + 0 = 0 + (1000 x u2)

u2 = \frac{2000}{1000} x 5

    = 10 m/s

Hence after collision, car moves at a velocity of 10 m/s

3 0
3 years ago
NEED HELP WITH THIS PLEASE
Jobisdone [24]

Answer:

A

Explanation:

5 0
3 years ago
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