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gtnhenbr [62]
2 years ago
14

The product(s) of a heated reaction of N-ethyl-N-methylpentanamide with sodium hydroxide would be __________. The product(s) of

a heated reaction of N-ethyl-N-methylpentanamide with sodium hydroxide would be __________. pentanoic acid and ethylmethylamine sodium propanoate and pentylamine sodium pentanoate and ethylmeth
Chemistry
1 answer:
olga2289 [7]2 years ago
6 0

Answer:

sodium pentanoate and ethylmethylamine

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Using the idea that reactions occur as a result of collisions between particles, explain why reaction rates depend on the temper
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Antimony has two naturally occuring isotopes, 121 Sb and 123 Sb . 121 Sb has an atomic mass of 120.9038 u , and 123 Sb has an at
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Answer:

Percentage abundance of 121 Sb is = 57.2 %

Percentage abundance of 123 Sb is = 42.8 %

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The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 121 Sb :

% = x %

Mass = 120.9038 u

For second isotope, 123 Sb:

% = 100  - x  

Mass = 122.9042 u

Given, Average Mass = 121.7601 u

Thus,  

121.7601=\frac{x}{100}\times 120.9038+\frac{100-x}{100}\times 122.9042

120.9038x+122.9042\left(100-x\right)=12176.01

Solving for x, we get that:

x = 57.2 %

<u>Thus, percentage abundance of 121 Sb is = 57.2 % </u>

<u>percentage abundance of 123 Sb is = 100 - 57.2 %  = 42.8 %</u>

6 0
3 years ago
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