Answer:
Explanation:
As the problem states that we have STP, these conditions are 1 atm of pressure and 273 K of temperature.
Now, the equation we must use to solve this:
PV = nRT
Solving for V:
<em>V = nRT/P</em>
<em>Where:</em>
<em>V: Volume in Liters</em>
<em>n: moles of the tin block</em>
<em>T: temperature in K</em>
<em>P: Pressure in atm</em>
<em>R: gas constant which is 0.082 L atm / K mol</em>
But also the problem is giving us the density data for all elements. In the case of Tin it is 7.31 g/cm³ or 7.31 g/mL, so, with the formula of density:
<em>d = m/V ----> V = m/d</em>
From the above formula, we can calculate the volume of tin so:
V = 95.04 / 7.31
<em>V = 13 mL</em>
This would be the volume of the tin block, but, we have this block at STP so we need to calculate the volume with the ideal gas equation above. We need the molecular mass of Tin which is 118.71 g/mol, so let's calculate the moles:
n = m/MM
n = 95.04 / 118.71 = 0.8 moles
Now, solving for V:
V = 0.8 * 0.082 * 273 / 1
<em>V = 17.91 L</em>
<em>And this would be the volume of the tin block at STP conditions.</em>
