Mass of C = 12g
mass of H = 1g
mass of O = 16g
mass of C2H5OH = 46g = 1 mole
1 mole of C2H5OH ------------ 46g
x moles of C2H5OH ----------- 230g
x = 5 moles of C2H5OH
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of C = 12g
mass of H = 1g
mass of C2H4 = 28g = 1 mole
1 mole of C2H4 -------------- 28g
x moles of C2H4 ------------- 560g
x = 20 moles of C2H4
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of S = 32g
mass of O = 16g
mass of SO2 = 64g = 1 mole
1 mole of SO2--------------------- 64g
x mole of SO2 -------------------- 0,64g
x = 0,01 moles of SO2
<span>Practically, the work needed to remove heat from a gas increases the colder.</span>
Answer:
The rate of reaction of a zero-order reaction is 0.0020 mol/L.
Explanation:
The rate expression of the zero order kinetic are :
![R=k[A]^o](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5Eo)
[A]= initial concentration of reactant
k = rate constant
R = rate of reaction
We have :
Rate constant of the reaction , k = 0.0020 mol/L s
R = 0.0020 mol/L s
The rate of reaction of a zero-order reaction is 0.0020 mol/L.
First calculate the electric charge used to deposit 1.0 g Pt
C = (1.0 g Pt) (1 mol Pt / 195.1 g Pt) ( 2 mol e / 1 mol Pt)
( 96485 C / 1 mol e)
C = 989.08 C
C = It
Where I is the current
T is the time
T = C / i
T = 989.08 C / 0.15 A
T = 6593.88 s
T = 1.83 hrs
