Answer:
57.48%
Explanation:
Calculate the mass of 1 mole of malachite:
MM Cu = 63.55
MM O = 16.00
MM H = 1.01
MM C = 12.01
A mole of malachite has:
2 moles of Cu
5 moles of O
2 moles of H
1 mole of C
MW Malachite = 2*MM(CU) + 5*MM(O) + 2*MM(H) + 1 *MM(C)
MW Malachite = 2*63.55 + 5*16.00 + 2*1.01 + 1*12.01
MW Malachite = 221.13
Mass of Cu in a mole of Malachite = 2*MM(CU) = 127.1
Now divide the mass of Cu by the mass of Malachite
Answer:
magnesium+ hydrochloric acid is the reactants
Explanation:
the reactants are always in the left and the products are always in the right by
magnesium+hydrochloric acid ⇒ magnesium chloride + hydrogen
by combining magnesium and hydrochloric acid it produces magnesium chloride and hydrogen.
hope this helps..
1 mol CuSO₄·5H₂O ----------- 5 mol H₂O
0,25 mol CuSO₄·5H₂O ---- Xmol H₂O
X = 5×0,25 = 1,25 mol H₂O
Only far from the Sun material condensed in the solar nebula, ice formed
