All categories

3 years ago

Chapter 7 Ionic Compounds with transition metals. please help!!! will give brainliest

Chemistry

1 answer:

gladu [14]3 years ago

3 0

Answer:

nickle bromide

Ferrous oxide

diFerrous oxide

Tin chloride

lead chloride

tin bromide

chromium phosphoride

ferrous fluoride

gold chloride

tin oxide

You might be interested in

How many moles of aluminum nitrate can be produced with 0.68 moles of lead nitrate?

Brrunno [24]

i have no idea can somebody help me too

6 0

3 years ago

Calculate the new pressure of a gas if the gas at 50 ˚C and 81.0 kPa is heated to 100 ˚C at a constant volume.

Debora [2.8K]

Answer:

93.5 kPa

Explanation:

Step 1: Given data

Initial pressure (P₁): 81.0 kPa

Initial temperature (T₁): 50 °C

Final pressure (P₂): ?

Final volume (T₂): 100 °C

Step 2: Convert the temperatures to the Kelvin scale

When working with gases, we need to consider the absolute temperature. We will convert from Celsius to Kelvin using the following expression.

K = °C + 273.15

T₁: K = 50°C + 273.15 = 323 K

T₂: K = 100°C + 275.15 = 373 K

Step 3: Calculate the final pressure of the gas

At a constant volume, we can calculate the final pressure of the gas using Gay-Lussac's law.

P₁/T₁ = P₂/T₂

P₂ = P₁ × T₂/T₁

P₂ = 81.0 kPa × 373 K/323 K

P₂ = 93.5 kPa

7 0

3 years ago

ANSWER ASAP

ArbitrLikvidat [17]

Answer:

c. 3.00 M HCl

Explanation:

From dilution formula

C1V1 = C2V2

C1=?, V1= 10.0ml, C= 1.5, V2= 20.0ml

Substitute and Simplify

C1×10= 1.5×20

C1= 3.00M

5 0

3 years ago

If you use a horizontal force of 32.0 N to slide a 12.5 kg wooden crate across a floor at a constant velocity, what is the coeff

sergejj [24]

Answer:

Value of coefficient of kinetic friction is 0.26 .

Explanation:

Given:

Mass of wooden crate, m = 12.5 kg.

Horizontal force to keep the block moving with constant velocity, F = 32.0 N.

Since, the block is moving with constant velocity.

So, net force experience by it is zero.

Therefore, fore of friction is equal to applied force.

Now, force of friction , $F=\mu_kN$ ( here $\mu_k$ is coefficient of kinetic friction and N is normal force)

Therefore, $\mu_kN=\mu_k\times mg=\mu_k\times 12.5 \times 9.8=122.5\times \mu_k$

Now, both forces are equal.

$122.5\times \mu_k=32\\\mu_k=\dfrac{32}{122.5}=0.26$

The value of coefficient of kinetic friction is 0.26 .

Hence, it is the required solution.

6 0

4 years ago

Write the mechanism for the two steps of the hydroboration/oxidation reaction of indene

iVinArrow [24]

It's difficult to write it down, but I'll attach you a good example of hydroboration of indene. I hope you'll find it helpful.

5 0

3 years ago