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givi [52]
4 years ago
11

If a fog forms over a lake what two changes of state must occur to produce the fog ​

Chemistry
1 answer:
xeze [42]4 years ago
4 0

Answer:

Evaporation and Condensation... Hope this helps : )

Explanation:

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The equation X + Y yields 
masha68 [24]
Most likely the equation yields a new compound XY. This is a synthesis reaction. <span>Synthesis reaction is a reaction where two or more substances combine to form a new compound. It is a reaction which releases energy in the form of heat and light. Therefore, it is an exothermic reaction.</span>
6 0
3 years ago
Give the SI base unit of each of these quantities. Enter the abbreviation rather than the name of the unit. mass: __________--le
Vladimir [108]

Answer:  mass : kg, length: meter, time: second, temperature: Kelvin

Explanation:

Mass is defined as the amount of matter contained in the body.

Its units are kg, gram, milligram which are inter convertible.

S.I or M.K.S system has seven fundamental units which are used to find derived units

1) Mass - Kilogram

2) Length - meter

3) Time - Seconds

4) Electric Current - Ampere

5) Amount of substance - Moles

6) Intensity of light - Candela

7) Temperature - Kelvin

Thus SI base unit of each of these quantities are kg, meter, second, and Kelvin

4 0
4 years ago
Help please I got the back but I’m struggling with the front
musickatia [10]
41. Mercury,Venus, Earth,mars,Jupiter, Saturn,Uranus and Neptune
42. Nebula - Their birth places are huge, cold clouds of gas and dust
8 0
3 years ago
A researcher dispenses distilled deionized water from a 20-ml volumetric pipet into an empty 8.4376 g weighting bottle. If the t
bonufazy [111]

As given that some volume of water has been dispensed say "x mL"

The initial weight of bottle =8.4376 g

The final weight of bottle + water =28.5845 g

So weight of water transferred = 28.5845 g - 8.4376 g = 20.1469 g

Now there is a relation between density, mass and volume

density = mass / volume

Therefore

Volume = mass / density

So volume of water dispensed = mass dispensed / density =20.1469 g / 0.9967867 g/ml.

Volume of water = 20.2118467 mL

 

7 0
4 years ago
Preparation of Standard Buffer for Calibration of a pH Meter The glass electrode used in commercial pH meters gives an electrica
lana66690 [7]

Answer:

  • Mass of NaH₂PO₄·H₂O = 8.542 g
  • Mass of Na₂HPO₄ = 5.410 g

Explanation:

Keeping in mind the equilibrium:

H₂PO₄⁻ ↔ HPO₄⁻² + H⁺

We use the Henderson-Hasselbalch equation (H-H):

pH = pka + log\frac{[A^{-}]}{[HA]}

For this problem [A⁻] = [HPO₄⁻²] and [HA] = [H₂PO₄⁻]

From literature we know that pka = 7.21, from the problem we know that pH=7.00 and that

[HPO₄⁻²] + [H₂PO₄⁻] = 0.100 M

From this equation we can <u>express [H₂PO₄⁻] in terms of [HPO₄⁻²]</u>:

[H₂PO₄⁻] = 0.100 M - [HPO₄⁻²]

And then replace [H₂PO₄⁻] in the H-H equation, <u>in order to calculate [HPO₄⁻²]</u>:

7.00=7.21+log\frac{[HPO4^{-2}] }{0.100 M-[HPO4^{-2}]} \\-0.21=log\frac{[HPO4^{-2}] }{0.100 M-[HPO4^{-2}]}\\10^{-0.21} =\frac{[HPO4^{-2}] }{0.100 M-[HPO4^{-2}]}\\0.616*(0.100M-[HPO4^{-2}])=[HPO4^{-2}]\\0.0616 M = 1.616*[HPO4^{-2}]\\0.03812 M =[HPO4^{-2}]

With the value of  [H₂PO₄⁻],<u> we calculate [HPO₄⁻²]</u>:

[HPO₄⁻²] + 0.0381 M = 0.100 M

[HPO₄⁻²] = 0.0619 M

Finally, using the concentrations, the volume, and the molecular weights; we can calculate the weight of each substance:

  • Mass of NaH₂PO₄·H₂O = 0.0619 M * 1 L * 138 g/mol = 8.542 g
  • Mass of Na₂HPO₄ = 0.0381 M * 1 L * 142 g/mol = 5.410 g

8 0
4 years ago
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