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rodikova [14]
3 years ago
10

A polygon is shown on the graph: A polygon is shown on a coordinate plane. The vertices are A at negative 6 comma 5, B at negati

ve 6 comma 2, C at negative 2 comma 2, and D at negative 2 comma 6. If the polygon is translated 4 units down and 5 units right, what will the coordinates of the new image be? Use prime notation in expressing the new coordinates. (5 points)
Mathematics
1 answer:
Delvig [45]3 years ago
8 0

Translating 4 units down and 5 units right means that you add 5 to the x coordinate, and subtract 4 from the y coordinate.

So, for example, we have

A' = (-6+5, 5-4)=(-1,1)

and so on for the other points.

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Will is selling T-shirts for $15 and sweatshirts for $20 at the basketball game. Wills club team needs to raise over $200 for th
Paladinen [302]

Answer:

X = 0     4     8     12

Y =  10   7     4      1

Step-by-step explanation:

Given:

Cost of one T shirt = $15

Cost  of one sweater = $ 20

To find :

The graph that will represent both number of T-shirts and sweatshirts = ?

Solution:

Let the number of t-shirts be x

The number of sweaters  be y

They want to rise a found of $200

Then  the equation to represent this situation is

15x + 20y = 200

By trial and error method

15(12) + 20(1) = 200

15(8) + 20(4) = 200

15(0) + 20(10) = 200

15(4) + 20(7) = 200

8 0
3 years ago
Please answer this question
Bogdan [553]
C=(1/4)*circumference
Area=pq+3.142r^2
60*3.142=pq+3.142p^2
q=((1/4)*2p*3.142)+2*3.142
q=1.571p+6.284
188.52=1.571p^2+6.284p+3.142p^2
188.52=4.713p^2+6.284p
188520=4713p^2+6284p
3 0
3 years ago
What is the direct variation equation if y varies directly with x and y = –6 when x = –36?
Vinil7 [7]
Direct variation is
y=kx
subsitute
-6=-36k
diivde both sdies by -36
1/6=k

the equation is
y=1/6x or B
8 0
3 years ago
In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders o
melomori [17]

Answer:

A. We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B. Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

C. z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

D. z_{\alpha/2}=-1.96  z_{1-\alpha/2}=1.96

E. Fail to the reject the null hypothesis

F. So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.  

Step-by-step explanation:

Data given and notation

n=362 represent the random sample taken

X=33 represent the number of orders not accurate

\hat p=\frac{33}{363}=0.0912 estimated proportion of orders not accurate

p_o=0.10 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

A: Write the claim as a mathematical statement involving the population proportion p

We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B: State the null (H0) and alternative (H1) hypotheses

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

C: Find the test statistic

Since we have all the info required we can replace in formula (1) like this:  

z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

D: Find the critical value(s)

Since is a bilateral test we have two critical values. We need to look on the normal standard distribution a quantile that accumulates 0.025 of the area on each tail. And for this case we have:

z_{\alpha/2}=-1.96  z_{1-\alpha/2}=1.96

P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

E: Would you Reject or Fail to Reject the null (H0) hypothesis.

Fail to the reject the null hypothesis

F: Write the conclusion of the test.

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.  

6 0
3 years ago
The question is jimmy scores is in the bottom 25% of the scores, but he does not have the lowest score. What is one possible val
Mariulka [41]

Answer:

50% duhh

Step-by-step explanation:

25% is also a equation

4 0
2 years ago
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