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Elena-2011 [213]
3 years ago
10

I have 14 but need the answer to 18. ​

Mathematics
1 answer:
nignag [31]3 years ago
5 0

Answer:

18.85 mm.

7.73 mm^2.

Step-by-step explanation:

The side of the square =  sqrt 36 = 6 mm.

Now this side = the diameter of the circle.

So the circumference of the circle = π  * 6 =  18.85 mm.

The answer to the second part

= area of the square - area of the circle

= 36 -  π *3^2

= 36 - 28.27

= 7.73 mm^2.

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tigry1 [53]

Answer:

Step-by-step explanation:

1 4/5*5/6

3/2 or 1 1/2

3 0
2 years ago
Please answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!
kramer

Answer:

MN = 4

m∠MLN = 42°

Step-by-step explanation:

If ΔMLN is congruent to ΔYZX, then

ML ↔ YZ   MN ↔ YX   LN ↔ ZX   ∠M ↔ ∠Y   ∠L ↔ ∠Z   ∠N ↔ ∠X

and all those correspondences are congruent when the triangles are congruent

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2 years ago
Jailyn has ½ of a pizza left over. She wants to share the pizza with 3 of her friends. What fraction of the original pizza will
N76 [4]

Answer:

Jailyn and her 3 friends will each receive 1/8 of the original pizza.

Step-by-step explanation:

Given that Jailyn has ½ of a pizza left over and she is sharing that with 3 friends, it means that the left over will be divided in 4 pieces and you have to divide 1/2 by 4 to find the fraction of the original pizza that Jailyn and her 3 friends will each receive:

\frac{1}{2}÷4= \frac{1}{2}÷\frac{4}{1} = \frac{1*1}{2*4} = \frac{1}{8}

According to this, the answer is that Jailyn and her 3 friends will each receive 1/8 of the original pizza.

8 0
3 years ago
At a football game
natka813 [3]
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3 0
3 years ago
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What is partial derivative of z=(2x+3y)^10 with respect to x,y?
maw [93]
Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.

\dfrac\partial{\partial x}(2x+3y)^{10}=10(2x+3y)^9\times2=20(2x+3y)^9

\dfrac\partial{\partial y}(2x+3y)^{10}=10(2x+3y)^9\times3=30(2x+3y)^9

Or, if you actually did want the second order derivative,

\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8

and in case you meant the other way around, no need to compute that, as z_{xy}=z_{yx} by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because z is a polynomial).
3 0
3 years ago
Read 2 more answers
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