It's a trick question because all of them contain both iconic and covalent bonds.
Hope it helps!! :) have fun
Answer:
The final volume of the sample of gas
= 0.000151 ![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
Explanation:
Initial volume
= 200 ml = 0.0002
Initial temperature
= 296 K
Initial pressure
= 101.3 K pa
Final temperature
= 336 K
Final pressure
= K pa
Relation between P , V & T is given by
![P_{1} \frac{V_{1} }{T_{1} } = P_{2} \frac{V_{2} }{T_{2} }](https://tex.z-dn.net/?f=P_%7B1%7D%20%5Cfrac%7BV_%7B1%7D%20%7D%7BT_%7B1%7D%20%7D%20%3D%20P_%7B2%7D%20%5Cfrac%7BV_%7B2%7D%20%7D%7BT_%7B2%7D%20%7D)
Put all the values in the above equation we get
![101.3 (\frac{0.0002}{296} )= 152 (\frac{V_{2} }{336} )](https://tex.z-dn.net/?f=101.3%20%28%5Cfrac%7B0.0002%7D%7B296%7D%20%29%3D%20152%20%28%5Cfrac%7BV_%7B2%7D%20%7D%7B336%7D%20%29)
= 0.000151 ![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
This is the final volume of the sample of gas.
Answer:
Moles of BCl₃ needed = 0.089 mol
Explanation:
Given data:
Moles of BCl₃ needed = ?
Mass of HCl produced = 10.0 g
Solution:
Chemical equation:
BCl₃ + 3H₂O → 3HCl + B(OH)₃
Number of moles of HCl:
Number of moles = mass/molar mass
Number of moles = 10.0 g/ 36.46 g/mol
Number of moles = 0.27 mol
Now we will compare the moles of HCl with BCl₃.
HCl : BCl₃
3 : 1
0.27 : 1/3×0.27 = 0.089 mol