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Answer:
Q = 4.056 J
Explanation:
∴ m = 406.0 mg = 0.406 g
∴ <em>C </em>= 1.85 J/g.K
∴ T1 = 33.5°C ≅ 306.5 K
∴ T2 = 38.9°C = 311.9 K
⇒ ΔT = 311.9 - 306.5 = 5.4 K
⇒ Q = (0.406 g)(1.85 J/gK)(5.4 K)
⇒ Q = 4.056 J
25 gigaseconds is equal to 2,500,000,000,000 centiseconds
Use the equation Q = mCT.
Q is the amount of energy in joules.
m is the mass in grams.
C is the specific heat of water (4.184 J/g °C).
T is the change in temperature.
0.700 pints = 331.224 g of water
Q = (331.224 g)(4.184 J/g °C)(100° C - 30° C)
Q = 97,008.885 J
Divide by 1,000 to convert to kilojoules:
97.009 kJ
