Answer:
Molarity: 0.522M
Percentage by mass: 2.36 (w/w) %
Explanation:
Formic acid, HCOOH reacts with NaOH as follows:
HCOOH + NaOH → NaCOOH + H₂O
To solve this question we must find the moles of NaOH added = Moles formic acid. Taken into account the dilution that was made we can find the moles -And molarity of formic acid and its percentage by mass as follows:
<em>Moles NaOH = Moles HCOOH:</em>
0.01580L * (0.1322mol / L) =0.002089 moles HCOOH
<em>Moles in the original solution:</em>
0.002089 moles HCOOH * (25mL / 10mL) = 0.005222 moles HCOOH
<em>Molarity of the solution:</em>
0.005222 moles HCOOH / 0.01000L =
<h3>0.522M</h3>
<em>Mass HCOOH in 1L -Molar mass: 46.03g/mol-</em>
0.522moles * (46.03g / mol) = 24.04g HCOOH
<em>Mass solution:</em>
1L = 1000mL * (1.02g / mL) = 1020g solution
<em>Mass percent:</em>
24.04g HCOOH / 1020g solution * 100
2.36 (w/w) %
Answer:
It will turn red
Explanation:
Bases will turn the litmus paper (impregnated with an acid-base indicator) blue.
Acids will turn turn the litmus paper (impregnated with an acid-base indicator) red.
Since the produced HCl is a strong acid, the litmus paper will turn red, when touching the HCl.
The red shows the presence of an acid, in this case HCl.
Answer:
In addition, carbonated beverages may serve as an acid load and thus may raise gastric acid volume, leading to increased likelihood of gastro‐oesophageal reflux. Two studies have demonstrated that carbonated beverages can reduce the oesophageal pH < 4 and potentially cause GERD‐related symptoms.
Explanation:
<h3>
Answer:</h3>
8CO₂
<h3>
Explanation:</h3>
We are given;
- Butane is a hydrocarbon in the homologous series known as alkane.
We are required to determine the other product produced in the combustion of butane apart from water.
- We know that the complete combustion of alkane yields carbon dioxide and water.
- Therefore, combustion of butane will yield carbon dioxide and water.
- The balanced equation for the complete combustion of butane will be;
2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O
Answer:
Described by a redox reaction below
Explanation:
Iron(III) oxide is an ionic compound, since it consists of a metal, iron, and a nonmetal, oxygen.
Ionic compounds are formed when metals lose their valence electrons in order to have an octet in their previous shell and donate them to nonmetal atoms, so that nonmetals fill their outer shell to have an octet.
As a result, positive ions (cations) and negative ions (anions) are formed. When iron reacts with oxygen, the following reaction takes place:
This is a redox (oxidation–reduction) reaction, since we have electron loss and gain. Four iron atoms lose a total of 12 electrons to obtain a +3 charge in the final compound, while 3 oxygen molecules gain these 12 electrons to become 6 oxide anions with a -2 charge.
