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Elis [28]
3 years ago
12

Following a collision between a large spacecraft and an asteroid, a copper disk of radius 28.0 m and thickness 1.20 m, at a temp

erature of 850°C, is floating in space, rotating about its axis with an angular speed of 20.0 rad/s. As the disk radiates infrared light, its temperature falls to 20.0°C. No external torque acts on the disk.
A) Find the change in kinetic energy of the disk.
B) Find the change in internal energy of the disk.
C) Find the amount of energy it radiates.

Physics
1 answer:
coldgirl [10]3 years ago
3 0

Answer:

A. 9.31 x10^10J

B. -8.47x10 ^ 12J

C. 8.38x 10^12J

Explanation:

See attached file pls

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All BUT one factor will increase the work output of a machine and decrease the amount of thermal energy created and released. Th
Serggg [28]
I would say C because extra friction would make the machine work more and therefore create more heat.
6 0
4 years ago
Read 2 more answers
To practice Problem-Solving Strategy 15.1 Mechanical Waves. Waves on a string are described by the following general equation y(
NeX [460]

Answer:

The transverse displacement is   y(1.51 , 0.150) = 0.055 m    

Explanation:

 From the question we are told that

     The generally equation for the mechanical wave is

                    y(x,t) = Acos (kx -wt)

     The speed of the transverse wave is v = 8.25 \ m/s

     The amplitude of the transverse wave is A = 5.50 *10^{-2} m

     The wavelength of the transverse wave is \lambda = 0540 m

      At t= 0.150s , x = 1.51 m

 The angular frequency of the wave is mathematically represented as

          w = vk

Substituting values  

         w = 8.25 * 11.64

        w = 96.03 \ rad/s

The propagation constant k is mathematically represented as

                  k = \frac{2 \pi}{\lambda}

Substituting values

                  k = \frac{2 * 3.142}{0. 540}

                   k =11.64 m^{-1}

Substituting values into the equation for mechanical waves

      y(1.51 , 0.150) = (5.50*10^{-2} ) cos ((11.64 * 1.151 ) - (96.03  * 0.150))

       y(1.51 , 0.150) = 0.055 m    

4 0
4 years ago
The process of blood cell formation is called
Andreyy89
Hemapoteisis



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7 0
3 years ago
When developing an experimental design, which action could a scientist take to improve the quality of the results?
worty [1.4K]

Answer:

B

Explanation:

This helps improve the quality.

4 0
3 years ago
Determine the stresses of the light bar and support wire
Lisa [10]

Tbar = Tension of the Light Bar

Twire = Tension of the Wire

Newton First Law About Force :

Fx = 0

Tbar cos 45° - Twire cos 25° = 0

Twire = 0.78 Tbar ... (i)

Fy = 0

Tbar sin 45° - Twire sin 25° - 1 = 0 ... (ii)

Subtitute (i) into (ii) :

Tbar sin 45° - 0.78 Tbar sin 25° - 1 = 0

Tbar = 2.563 kN ... (iii)

Subtitute (iii) into (i) :

Twire = 0.78 (2.563)

Twire = 1.999 kN

6 0
2 years ago
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