Ask question

Ask question

All categories

Romashka-Z-Leto [24]

3 years ago

7

How much voltage is required to run 0.054 A of current through a 15 resistor? Use AV=IR. O A. 2.8 x 102 v O B. 1.2 V O C. 3.6 x

10-3 v O D. 0.81 V

2 answers:

olga55 [171]3 years ago

6 0

Answer:the answer is D

Explanation:

Plug variables in and calculate

prisoha [69]3 years ago

5 0

Answer:

D. 0.81 V

Explanation:

(delta)V=IR

0.054 a * 15

0.81 V

You might be interested in

Which is the correctly balanced equation for the reaction of rust, Fe2O3, and hydrochloric acid, HCl?

Mariana [72]

Answer: Option (c) is correct answer.

Explanation:

The given reaction equation is as follows.

$Fe_{2}O_{3} + HCl \rightarrow FeCl_{3} + H_{2}O$

The number of atoms on reactant side are as follows.

Fe = 2
O = 3
H = 1
Cl = 1

The number of atoms on product side are as follows.

Fe = 1
O = 1
H = 2
Cl = 3

Therefore, in order to balance the equation we will balance the number of atoms in both reactant and product side.

Since number of Fe atoms in reactant side is 2, therefore, multiply $FeCl_{3}$ by 2 in the product side.

Number of O atoms in reactant side is 3, therefore, multiply $H_{2}O$ by 3 in the product side.

Now, the number of H atoms on product side is 6, therefore, multiply HCl by 6 in the reactant side.

The number of chlorine atoms on both reactant and product side equals 6.

Thus, the equation will become as follows.

$Fe_{2}O_{3} + 6HCl \rightarrow 2FeCl_{3} + 3H_{2}O$

Hence, the equation is balanced.

5 0

4 years ago

Read 2 more answers

An electron (charge −e=−1.60×10−19C−e=−1.60×10−19C) is at rest at a distance 1.00×10−10 m 1.00×10−10m from the center of a nucle

shtirl [24]

Answer:

$-9.45\times10^{-16} \text{ J}$

Explanation:

According to Coulomb's law, the force of attraction between two point charges, $q_1$ and $q_2$ , separated by a distance $d$ is given by

$F = k\dfrac{q_1q_2}{d^2}$

$k$ is a constant with a value of $9\times10^9\text{ F/m}$ .

When we substitute the values from the question,

$F = (9\times10^9\text{ F/m})\dfrac{(-1.60\times10^{-19} \text{ C})\times(+1.31\times10^{-17}\text{ C})}{(1.00\times10^{-10}\text{ m})^2} = -1.89\times10^{-6} \text{ N}$

This value is negative because it is in a direction towards the positive charge.

The work done in moving the electron from the nucleus is

$W = F\times r$

$W = (-1.89\times 10^{-6} \text{ N})\times(5.00\times10^{-10}\text{ m}) = -9.45\times10^{-16} \text{ J}$

This is negative because work is done on the electron, not by it.

3 0

3 years ago

A billiard ball with a mass of 1.5kg is moving at 25m/s and strikes a second ball with a mass of 2.3 kg that is motionless. Find

aliya0001 [1]

Answer:

The velocity of the second ball after the collision will be 16.3 m/s.

Step-by-Step Explanation:

Law of conservation of momentum states that the total momentum of an isolated remains the same before and after the collision.

Let: mass of the first ball = m1 = 1.5 kg

mass of the second ball = m2 = 2.3 kg

Momentum before the collision:

velocity of the first ball = v1 = 25 m/s

velocity of the second ball = v2 = 0 m/s

[tex] Initial momentum = m1v1 + m2v2 = 1.5*25 + 2.3*0 = 37.5 kgm/s [\tex]

Momentum after the collision:

velocity of the first ball = v1 = 0 m/s

velocity of the second ball = v2 = x

[tex]momentum after the collision= m1v1 + m2v2 = 1.5*0 + 2.3*x = 2.3*x[\tex]

According to law of conservation of momentum:

Initial momentum = Momentum after collision

37.5 = 2.3*x

⇒ x = 37.5/2.3

x = 16.3 m/s

4 0

3 years ago

Do deaf children go through the four stages of acquiring language? Use what you’ve read in the chapter to explain why or why not

sdas [7]

No deaf children dont. im deaf and i dident go through those stages.

4 0

4 years ago

When the north pole of a magnet is moved towards the center of a loop of wire containing a galvanometer, the needle of the galva

andriy [413]

Answer:

Moving the magnet away from the center of the loop with its south pole facing the center of the loop.

Explanation:

Electromagnetic induction is due to a rapidly changing magnetic field, or loop area. The poles of the magnet induce current in the loop but in the opposite direction, depending on the direction of their relative motion. An approaching north pole will induce an anticlockwise current in the loop, while an approaching south pole will do the reverse. To get the galvanometer to flicker in the same direction as of that when the north pole was approaching, we move the magnet away from the center of the loop with its south pole facing the center of the loop.

6 0

3 years ago