Answer: The force was 13.92 Newtons.
Explanation:
First, let's recall the second Newton's law:
The net force is equal to the mass times the acceleration, or:
F = m*a
where:
F = force
m = mass
a = acceleration.
When the player hits the ball with the bat, he applies a force that accelerates the ball for a small period of time, that increases greatly the speed of the ball.
In this case, we know that:
the mass of the ball is 0.145 kg
The acceleration of the ball is 96m/s^2
Then we can input those values in the above equation to find the force.
F = 0.145kg*96m/s^2 = 13.92 N
The force was 13.92 Newtons.
The cats have full bowls in the morning and afternoon, Katy can assume that the cats do not eat in the morning or afternoon. The bowls are replenished in the evening, which suggests that they become empty in the evening, which suggest that the pattern is that the cats eat in the evening so your answer would be C. Hope this helps. ;)
Answer:
The sled needed a distance of 92.22 m and a time of 1.40 s to stop.
Explanation:
The relationship between velocities and time is described by this equation:
, where
is the final velocity,
is the initial velocity,
the acceleration, and
is the time during such acceleration is applied.
Solving the equation for the time, and applying to the case:
, where
because the sled is totally stopped,
is the velocity of the sled before braking and,
is negative because the deceleration applied by the brakes.
In the other hand, the equation that describes the distance in term of velocities and acceleration:
, where
is the distance traveled,
is the initial velocity,
the time of the process and,
is the acceleration of the process.
Then for this case the relationship becomes:
.
<u>Note that the acceleration is negative because is a braking process.</u>
Answer:
Explanation:
We know that the volume V for a sphere of radius r is

If we got an uncertainty
the formula for the uncertainty of V is:

We can calculate this uncertainty, first we obtain the derivative:


And using it in the formula:



The relative uncertainty is:



Using the values for the problem:

This is, a percent uncertainty of 4.77 %