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oksian1 [2.3K]
3 years ago
6

A tall pea plant (TT) is crossbred with a short pea plant (tt). The following Punnett square shows the separated alleles for two

pea plants.
Punnett square showing female parent across the top with a phenotype of tall and a genotype of TT and a male parent across the side with a phenotype of short and a genotype of tt. Inside the top left box 1 is written, inside the top right box 2 is written, inside the bottom left box 3 is written, inside the bottom right box 4 is written.

Which of the following shows the correct match of the box numbers and the genotype of the offspring?

1 = TT; 2 = TT; 3 = Tt; 4 = Tt
1 = TT; 2 = Tt; 3 = Tt; 4 = tt
1 = TT; 2 = Tt; 3 = Tt; 4 = Tt
1 = Tt; 2 = Tt; 3 = Tt; 4 = Tt
Chemistry
1 answer:
Leto [7]3 years ago
6 0
The last one ; box 1- Tt, 2= Tt, 3= Tt, 4=Tt,
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<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

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W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

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