Na₂S(aq) + Cd(NO₃)₂(aq) = CdS(s) + 2NaNO₃(aq)
v=25.00 mL
c=0.0100 mmol/mL
M(Na₂S)=78.046 mg/mmol
n(Na₂S)=n{Cd(NO₃)₂}=cv
m(Na₂S)=M(Na₂S)n(Na₂S)=M(Na₂S)cv
m(Na₂S)=78.046*0.0100*25.00≈19.5 mg
1. The molar mass of the unknown gas obtained is 0.096 g/mol
2. The pressure of the oxygen gas in the tank is 1.524 atm
<h3>Graham's law of diffusion </h3>
This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e
R ∝ 1/ √M
R₁/R₂ = √(M₂/M₁)
<h3>1. How to determine the molar mass of the gas </h3>
- Rate of unknown gas (R₁) = 11.1 mins
- Rate of H₂ (R₂) = 2.42 mins
- Molar mass of H₂ (M₂) = 2.02 g/mol
- Molar mass of unknown gas (M₁) =?
R₁/R₂ = √(M₂/M₁)
11.1 / 2.42 = √(2.02 / M₁)
Square both side
(11.1 / 2.42)² = 2.02 / M₁
Cross multiply
(11.1 / 2.42)² × M₁ = 2.02
Divide both side by (11.1 / 2.42)²
M₁ = 2.02 / (11.1 / 2.42)²
M₁ = 0.096 g/mol
<h3>2. How to determine the pressure of O₂</h3>
From the question given above, the following data were obtained:
- Volume (V) = 438 L
- Mass of O₂ = 0.885 kg = 885 g
- Molar mass of O₂ = 32 g/mol
- Mole of of O₂ (n) = 885 / 32 = 27.65625 moles
- Temperature (T) = 21 °C = 21 + 273 = 294 K
- Gas constant (R) = 0.0821 atm.L/Kmol
The pressure of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both side by V
P = nRT / V
P = (27.65625 × 0.0821 × 294) / 438
P = 1.524 atm
Learn more about Graham's law of diffusion:
brainly.com/question/14004529
Learn more about ideal gas equation:
brainly.com/question/4147359
Answer:
6. a. 5.53 (m/m) %; b. 0.7490M
7. 0.156M
Explanation:
6. In the solution of KCl, there are 1.396g of KCl in 25.225g of solution. As mass/mass percent is:
Mass solute / Mass solution * 100
The mass/mass percent of KCl is:
a. 1.396g KCl / 25.225g solution * 100
5.53 (m/m) %
b. Molarity is moles of solute per liters of solution:
<em>Moles KCl -Molar mass: 74.55g/mol-:</em>
1.396g KCl * (1mol / 74.55g) = 0.018726 moles KCl
<em>Volume in liters: 25mL = 0.025L</em>
Molarity:
0.018726 moles KCl / 0.025L = 0.7490M
7. 0.90% means 0.90g of NaCl in 100g of solution:
<em>Moles NaCl -Molar mass: 58.44g/mol-:</em>
0.90g NaCl * (1mol / 58.44g) = 0.0154 moles NaCl
<em>Volume in Liters:</em>
100g * (1mL / 1.01g) = 99mL = 0.099L
Molarity:
0.0154 moles NaCl / 0.099L =
0.156M
<h3>
Answer:</h3>
7.51 × 10²² atoms S
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
4.00 g S
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of S - 32.07 g/mol
<u>Step 3: Convert</u>
- Set up:

- Multiply:

<u>Step 4: Check</u>
<em>Follow sig figs and round. We are given 3 sig figs.</em>
7.51107 × 10²² atoms S ≈ 7.51 × 10²² atoms S