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Firlakuza [10]
3 years ago
11

How many moles of trifluoromethanoic acid (CHF3O3S) are present in 9.0345 × 1024 molecules of (CHF3O3S)?

Chemistry
1 answer:
timama [110]3 years ago
5 0
1 mole ------------ 6.02x10²³ molecules
? moles ----------- 9.0345x10²⁴ molecules

( 9.0345x10²⁴) x 1 / 6.02x10²³ =

9.0345x10²⁴ / 6.02x10²³ => 15.007 moles


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In a 5.609g of H20, how many molecules H20<br> arc<br> present?
nignag [31]

Answer:

1.88 x 10²³molecules of H₂O

Explanation:

Given parameters:

Mass of H₂O  = 5.609g

Unknown:

Number of molecules of  H₂O  = ?

Solution:

To solve this problem, we need to find the number of moles of given compound first.

 Number of moles  = \frac{mass}{molar mass}  

Molar mass of  H₂O = 2(1) + 16  = 18g/mol

 Number of moles  = \frac{5.609}{18}   = 0.31mole

From mole concept;

            1 mole of a substance contains 6.02 x 10²³molecules

       0.31 mole of H₂O will therefore contain 0.31 x 6.02 x 10²³molecules

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3 years ago
A certain compound is made up of one phosphorus (P) atom, three chlorine (Cl) atoms, and one oxygen (O) atom. What is the chemic
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3 years ago
A 45ml of a 4M solution of CaBr2 contains how many grams of CaBr2?
natta225 [31]

The required mass of calcium bromide is 35.98 grams.

<h3>What is molarity?</h3>

Molarity is any solution is define as the number of moles of solute present in per liter of solution as;

M = n/V, where

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Moles will be calculated by using the above equation as:

n = (4)(0.045) = 0.18 mole

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

  • W = given mass
  • M = molar mass

Mass of CaBr₂ = (0.18mol)(199.89g/mol) = 35.98g

Hence required mass of CaBr₂ is 35.98 grams.

To know more about molarity, visit the below link:
brainly.com/question/22283918

#SPJ1

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