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laiz [17]
3 years ago
9

Octasulfur reacts with pure oxygen to produce sulfur dioxide. Determine the percent

Chemistry
1 answer:
Margaret [11]3 years ago
5 0

Answer:

Octasulfur is just S8. Eight S atoms in

a sort of crown shape. Sulfur Dioxide is a gas, SO2. Does that help?

Explanation:

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4 0
3 years ago
Read 2 more answers
C2F4 effuses through a barrier at a rate of 4.6x10-6 mol/hour, while an unknown gas effuses at a rate of 5.8x10-6 mol/hour. What
umka21 [38]
The  molar mass  of  the unknown  compound  is   calculated   as   follows

let the unknown  gas be represented by   letter  Y

Rate of C2F4/  rate of  Y  = sqrt of   molar  mass of gas Y/ molar mass of  C2F4

 =  (4.6  x10^-6/ 5.8  x10^-6)  = sqrt  of  Y/ 100

remove  the  square  root  sign  by  squaring  in both  side

(4.6  x  10^-6 / 5.8  x10^-6)^2 =  Y/100

= 0.629 =Y/100

multiply  both side  by  100

Y=  62.9 is  the molar  mass of unknown  gas



5 0
3 years ago
Has encontrado problemas de eutrofización en Xochimilco. Los habitantes del lugar te preguntan cuál es el problema y les dices q
Musya8 [376]

Answer: I go search some information

Explanation:I come back with a answer

3 0
3 years ago
If 100 ml of a 0.5 M HCI Solution is diluted with water to 1000ml, what is the new concetration?
Vesna [10]

Answer:

0.05\ \text{M HCl}

Explanation:

V_1 = Initial volume = 100 mL

V_2 = Final volume = 1000 mL

M_1 = Initial concentration = 0.5 M

M_2 = Final concentration

We have the relation

\dfrac{M_1}{M_2}=\dfrac{V_2}{V_1}\\\Rightarrow M_2=M_1\dfrac{V_1}{V_2}\\\Rightarrow M_2=0.5\times \dfrac{100}{1000}\\\Rightarrow M_2=0.05\ \text{M HCl}

The new concentration is 0.05\ \text{M HCl}.

3 0
3 years ago
HELP PLSSSSSSSSSS
Nat2105 [25]

Answer:

ask your mom

Explanation:

copy this \pink{ \rule{999pt}{999999pt}}

and the result is here

btw if you want to change color change the \pink (if you want?)

\red{ \rule{999pt}{999999pt}}

8 0
2 years ago
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