The concentration of diluted solution is 0.756M.
From the question given above, the following data were obtained:
Volume of stock solution (V1) = 18.9 mL
Molarity of stock solution (M1) = 10 M
Volume of diluted solution (V2) = 250 mL
Molarity of diluted solution (M2) =?
We can obtain the molarity of the diluted solution by using the dilution formula as shown follow:
M1V1 = M2V2
10 × 18.9 = M2 ×250
189 = M2 × 250
Divide both side by 100
M2 = 189 / 250
M2 = 0.756 M
Therefore, the molarity of the diluted solution is 0.756 M.
Thus the concluded that concentration of the dilute acid is 0.756 M.
Learn more about concentration of diluted solution: brainly.com/question/10725862
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<em><u>look at the clues by it and try not to trust the links they trying to give u...</u></em>
<em><u>but i kinda dont know myself any periodic table i can look at?</u></em>
Answer:
the effects that the scientists are causing by manipulating varuables
In Fisher esterification, sulfuric acid is used as a catalyst and its function is to convert the carboxylic compound in its conjugate acid. This favours the nucleophilic attack of the alcohol. To act as a catalyst you need a strong acid, therefore sulphuric acid is suitable for this kind of reaction.
Answer : The value of 
is -49.6 kJ/mol
Explanation :
First we have to calculate the reaction quotient.
Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
The given balanced chemical reaction is,
The expression for reaction quotient will be :
![Q=\frac{[ADP][HPO_4^{2-}]}{[ATP]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BADP%5D%5BHPO_4%5E%7B2-%7D%5D%7D%7B%5BATP%5D%7D)
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Given:
![[ATP]](https://tex.z-dn.net/?f=%5BATP%5D)
= 5.0 mM
![[ADP]](https://tex.z-dn.net/?f=%5BADP%5D)
= 0.60 mM
![[HPO_4^{2-}]](https://tex.z-dn.net/?f=%5BHPO_4%5E%7B2-%7D%5D)
= 5.0 mM
Now put all the given values in this expression, we get
Now we have to calculate the value of .
The formula used for is:
............(1)
where,
= Gibbs free energy for the reaction = ?
= standard Gibbs free energy = -30.5 kJ/mol
R = gas constant = 
T = temperature = 
Q = reaction quotient = 
Now put all the given values in the above formula 1, we get:
Therefore, the value of is -49.6 kJ/mol
