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coldgirl [10]
2 years ago
14

Determine the identity of a cube of metal that measures 1.5 cm on each side and has a mass of 35.45g.

Chemistry
2 answers:
Ainat [17]2 years ago
7 0

Answer:10.501

Explanation:

Troyanec [42]2 years ago
3 0
The word identity is a mistake. The question asks for the density of a cube of metal with the measures and mass given.

Density = mass / volume

mass = 35.45 g

volume of a cube = (length of the side) ^ 3 = (1.5 cm)^3 = 3.375 cm^3

Density = 35.45 g / 3.375 cm^3 = 10.50 g / cm^3.

Answer: 10.50 g / cm^3
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Solid iron (III) oxide reacts with hydrogen gas to form iron and water. How many grams of iron are produced when 440.23 grams of
Nookie1986 [14]

When 440.23 grams of iron(III) oxide are reacted with hydrogen gas, the amount of iron produced will be 307.66 grams

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

Fe_2O_3 + 3H_2 --- > 2Fe + 3H_2O

The mole ratio of iron(III) oxide to produced iron is 1:2.

Mole of 440.23 iron(III) oxide = 440.23/159.69 = 2.76 moles

Equivalent mole of produced iron = 2.76 x 2 = 5.52 moles

Mass of 5.52 moles of iron = 5.52 x 55.8 = 307.66 grams

More on stoichiometric calculations can be found here; brainly.com/question/27287858

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4 0
1 year ago
Calculate the electrical energy per gram of anode material for the following reaction at 298 K:
solmaris [256]

43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, <em>n</em>, equals 0.144 moles for each gram of the anode.

Let w_\text{max} represents the electrical energy produced.

w_\text{max} = n \cdot F \cdot E_\text{cell}, where

  • <em>n</em> is the <em>number of moles</em> electrons transferred,
  • <em>F</em> is the Faraday's constant,
  • <em>E</em>_\text{cell} is the cell potential,

<em>n </em>= 0.144 mol, as shown above, and

<em>F </em>= 96.486 kJ / (\text{V} \cdot \text{mol} \; \text{e}^{-}).

Therefore,

w_\text{max} = n \cdot F \cdot E\\\phantom{w_\text{max}} = 0.144 \times 96.486 \times 3.15 \\\phantom{w_\text{max}} = 43.8 \; \text{kJ}.

3 0
3 years ago
Given that a mass of a ball is (36.0 g), and the volume is (8.0 mL), what is the ball's density in g/mL?​
max2010maxim [7]

Answer:

4.5g/mL

Explanation:

Given parameters:

Mass of ball  = 36g

Volume of the ball  = 8mL

Unknown:

Density of the ball  = ?

Solution:

Density is the mass per unit volume of a substance.

          Density  = \frac{mass}{volume}  

So;

 Density  = \frac{36}{8}    = 4.5g/mL

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3 0
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Answer:

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