1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mice21 [21]
4 years ago
7

A dioxin-contaminated water source contains 0.085% dioxin by mass. how much dioxin is present in 2.5 l of this water?

Chemistry
1 answer:
erma4kov [3.2K]4 years ago
8 0
 The mass of dioxin  present in  2.5L of  water  is  2.125 grams

                calculation
c
onvert  the 2.5 l to Ml  =  2.5 x1000 = 2500 Ml

density  of  water  is =  1g/ml

mass  is  of  water is therefore =  density  x volume

= 2500 Ml  x 1g/ml = 2500 grams
by of the below  formula of  calculating  of % mass

that is  mass of the solute / mass  of   the solution  =  % mass 

let  the mass of  solute  be represented by y
mass  of solution = 2500 g
%  mass = 0.085% =  0.085/100  into  fraction

  by  subsituting  in the  formula 

  =y/2500= 0.085/100
  cross  multiplication

100y =212.5

divide both side   by 100

y=  2.125 grams

You might be interested in
Sheila's measured glucose level one hour after a sugary drink varies according to the normal distribution with μμ = 120 mg/dl an
Molodets [167]

Since the sample size is below 30, in this case we use the t statistic. The formula for t score is:

t = (x – u) / (σ / sqrt n)

where,

x = the level l = unknown

u = sample mean = 120 mg / dl

σ = standard deviation = 20 mg / dl

n = sample size or number of results = 5

Using the standard distribution tables for t, we can find the value of t given the probability (P = 0.15) and degrees of freedom (DOF).

t  = 1.036

Going back to the formula for t score:

1.036 = (x – 120) / (20 / sqrt 5)

x = 129.27 mg / dl = l

8 0
3 years ago
Consider the two gaseous equilibria: The values of the equilibrium constants K 1 and K 2 are related by
Sauron [17]

The question is missing parts. The complete question is as follows.

Consider the two gaseous equilibria involving SO2 and the corresponding equilibrium constants at 298K:

SO_{2}_{(g)} + \frac{1}{2}O_{2} ⇔ SO_{3}_{(g)}; K_{1}

2SO_{3}_{(g)} ⇔ 2SO_{2}_{(g)}+O_{2}_{(g)}; K_{2}

The values of the equilibrium constants are related by:

a) K_{1} = K_{2}

b) K_{2} = K_{1}^{2}

c) K_{2} = \frac{1}{K_{1}^{2}}

d) K_{2}=\frac{1}{K_{1}}

Answer: c) K_{2} = \frac{1}{K_{1}^{2}}

Explanation: <u>Equilibrium</u> <u>constant</u> is a value in which the rate of the reaction going towards the right is the same rate as the reaction going towards the left. It is represented by letter K and is calculated as:

K=\frac{[products]^{n}}{[reagents]^{m}}

The concentration of each product divided by the concentration of each reagent. The indices, m and n, represent the coefficient of each product and each reagent.

The equilibrium constants of each reaction are:

SO_{2}_{(g)} + \frac{1}{2}O_{2} ⇔ SO_{3}_{(g)}

K_{1}=\frac{[SO_{3}]}{[SO_{2}][O_{2}]^{1/2}}

2SO_{3}_{(g)} ⇔ 2SO_{2}_{(g)}+O_{2}_{(g)}

K_{2}=\frac{[SO_{2}]^{2}[O_{2}]}{[SO_{3}]^{2}}

Now, analysing each constant, it is easy to see that K_{1} is the inverse of K_{2}.

If you doubled the first reaction, it will have the same coefficients of the second reaction. Since coefficients are "transformed" in power for the constant, the relationship is:

K_{2}=\frac{1}{K_{1}^{2}}

8 0
3 years ago
How many moles is ( 1 x 10^9 ) molecules O2
Effectus [21]

Answer:

The answer is

1.66 \times  {10}^{ - 15}  \:  \: moles

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}   \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{1 \times  {10}^{9} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

1.66 \times  {10}^{ - 15}  \:  \: moles

Hope this helps you

4 0
3 years ago
What are the products of RbNO2 + BaCO3? <br><br> Please help!
Anton [14]

Answer:

RbCO3 +BaNO2

Explanation:

7 0
3 years ago
In the covalent bond between hydrogen and chlorine in the HCl molecule, where will the majority of shared electrons be found?
Mrac [35]
Nearer to the chlorine as it has a greater electronegativity 
5 0
3 years ago
Read 2 more answers
Other questions:
  • Please help i have a midterm tommorow
    6·1 answer
  • how many grams of barium sulfate will be formed upon the complete reaction of 25.6 grams of barium hydroxide with excess sulfuri
    10·1 answer
  • The rate law for a reaction is rate=k[A][B] Which one of the following statements is false? The rate law for a reaction is Which
    8·1 answer
  • Which is an example of gaining a static charge by conduction?
    8·1 answer
  • Which equation represents neutralization?
    9·1 answer
  • If a molecular formula is C8H12O2 , what is the empirical
    10·1 answer
  • Copper roofs on houses form patina (copper carbonates) over the course of years due to the reaction with oxygen, carbon dioxide
    13·1 answer
  • Question 13 (3 points)
    7·1 answer
  • What would happen if you tried to cut a piece of aluminum foil over and over again
    8·1 answer
  • Which molecule can't be exist?<br>A)NCl3 B)OF6 C)ONF3 D)PCl3<br>​
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!