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babymother [125]
3 years ago
13

Copper roofs on houses form patina (copper carbonates) over the course of years due to the reaction with oxygen, carbon dioxide

and water in the air. Which of the following statements is incorrect for this process?
A) The reaction has a low activation energy.
B) The reaction has a low reaction rate.
C) The formation of patina would occur faster during the summer than the winter.
D) The formation of patina would occur slower at higher altitudes due to lower concentration of reactant. E) Adding a catalyst would increase the rate of patina formation.
Chemistry
1 answer:
ale4655 [162]3 years ago
5 0

Answer:

The answer is "Choice A".

Explanation:

In this question, the choice A is wrong because when the copper panels on houses produce a patina (copper oxide) through occur as a consequence of reactions from oxygen and water in the air, these reaction does not have low activation energy because lower activation energy that is stored in a faster response rate.

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I need the 3 questions !!! About Rubidium (Rb) <br><br> ASAP PLEASE DUE IN LIKE 20 min
hjlf

Answer:

  1. 419kJ/mol  
  2. 5,0,0,+12
  3. That catches fire spontaneously

Explanation:

1. Topic: Chemistry

ElementFirst Ionization Energy (kJ/mol) Lithium520Sodium496Rubidium403Cesium376According to the above table, which is most likely to be the first ionization energy for potassium?  

  • 536kJ/mol  
  • 504kJ/mol  
  • 419kJ/mol  
  • 391kJ/mol  
  • 358kJ/mol

2. Topic: Chemistry, Atom

The correct set of four quantum numbers for the valence electrons of the rubidium atom   (Z=37)  is:  

  • 5,1,1,+12  
  • 5,0,1,+12  
  • 5,0,0,+12
  • 5,1,0,+12

3. Rubidium and cesium are pyrophoric. Here the term pyrophoric means:

  • That hardly catches fire
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5 0
3 years ago
Select all correct answers.
Jlenok [28]

Answer: It showed that all atoms contain electrons.

Explanation:

  • J.J. Thomson's experiments inside a cathode ray tube in the presence of an electric field showed that all atoms contain tiny negatively charged subatomic particles "electrons".
  • Also, Thomson's plum pudding model of the atom had negatively-charged electrons embedded within a positively-charged "soup."
  • Furthermore, Rutherford's gold foil experiment showed that the atom is mostly empty space with a tiny positively-charged nucleus.
  • Then, Rutherford proposed the nuclear model of the atom based on these results.
7 0
3 years ago
In another experiment, a 0.150 M BF4^-(aq) solution is prepared by dissolving NaBF4(s) in distilled water. The BF4^-(aq) ions in
Ilia_Sergeevich [38]

Answer:

A) Forward rate = 1.1934 × 10^(-4) M/min

B) I disagree with the claim

Explanation:

A) We are told that [HF] reaches a constant value of 0.0174 M at equilibrium.

The reversible reaction given to us is;

BF4-(aq) +H20(l) → BF3OH-(aq) + HF(aq)

From this, we can see that the stoichiometric ratio is 1:1:1:1

Thus, concentration of [BF4-] is now;

[BF4-] = 0.150 - 0.0174

[BF4-] = 0.1326 M

From the rate law, we are told the forward rate is kf [BF4-].

We are given Kf = 9.00 × 10^(-4) /min

Thus;

Forward rate = 9.00 × 10^(-4) /min × (0.1326M)

Forward rate = 1.1934 × 10^(-4) M/min

(B) The student claims that the initial rate of the reverse reaction is equal to zero can't be true because at equilibrium, rates for the forward and reverse reactions are usually equal.

Thus, I disagree with the claim.

3 0
3 years ago
A cool, yellow-orange flame is used to heat the crucible. Would this affect the mass of the crucible? If so, how?
s2008m [1.1K]

Answer:

yes

Explanation:

Usually, it would not affect the crucible, but depending on the temperature of the flame the enamel of the crucible may begin to melt and stick to the metal object being used to handle the crucible. This tiny amount that is melted off can cause very small changes in the original mass of the crucible, which although it is almost unnoticeable it is still there. Therefore, the answer to this question would be yes.

5 0
3 years ago
1. BaBr2(aq) + H2SO4(aq) →?<br> please balance the equation and predict the products
Andrew [12]

Answer:

BaBr2 (aq) + H2SO4 (aq) → BaSO4 (s) + 2 HBr (aq)

Explanation:

This is a precipitation reaction: BaSO4 is the formed precipitate.

4 0
3 years ago
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