7<n<8 is the right answer
Answer:
Domain: [0,infinity)
Range: [0,infinity)
X-intercept: (0,0)
Y-intercept: (0,0)
Step-by-step explanation:
Answer:
y = ![\frac{1}{5}(x^{2}-35x)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%28x%5E%7B2%7D-35x%29)
Step-by-step explanation:
Let the total numbers are n.
If the average of y numbers is x then we can form an equation
![\frac{y}{n}=x](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7Bn%7D%3Dx)
⇒ ![\frac{n}{y}=\frac{1}{x}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7By%7D%3D%5Cfrac%7B1%7D%7Bx%7D)
⇒ n =
--------(1)
Now 30 is added to the set of numbers then average becomes (x - 5)
![\frac{y+30}{n+1}=(x-5)](https://tex.z-dn.net/?f=%5Cfrac%7By%2B30%7D%7Bn%2B1%7D%3D%28x-5%29)
⇒ ![\frac{(n+1)}{(y+30)}=\frac{1}{(x-5)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28n%2B1%29%7D%7B%28y%2B30%29%7D%3D%5Cfrac%7B1%7D%7B%28x-5%29%7D)
⇒ (n + 1) = ![\frac{y+30}{x-5}](https://tex.z-dn.net/?f=%5Cfrac%7By%2B30%7D%7Bx-5%7D)
⇒ n =
- 1 ----- (2)
Now we equate the values of n from equation 1 and 2
=
- 1
y(x - 5) = x(y + 30) - x(x - 5) [ By cross multiplication ]
xy - 5y = xy + 30x - x² + 5x
xy - xy - 5y = 35x - x²
-5y = 35x - x²
x² - 35x = 5y
y = ![\frac{1}{5}(x^{2}-35x)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%28x%5E%7B2%7D-35x%29)
That's simple!!!
-12/19 = b/19
as denominators are same, you can cancel that.
b = -12
Answer:
its a such a hard questions i think you should ask to you're teacher ?