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krek1111 [17]
4 years ago
10

What is the molarity of a solution that contains 0.4mol KCl in 3.5L of solution?

Chemistry
1 answer:
OLga [1]4 years ago
3 0

Answer:

0.1143M

Explanation:

if one 0.4moles=3.5l what about 1litre

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Atoms and the chemical bonds that connect them cannot be observed with your eyes, so it is necessary to use a
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Answer: d. both (b) and (c)

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Atoms are too small to be seen on microscopes, so we model them based on theories.

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3 years ago
BaCl2(aq) + Na2CO3(aq) BaCO3(s) + NaCl(aq
Vitek1552 [10]
This is the equation balanced:

<span>BaCl2(aq) + Na2CO3(aq) = BaCO3(s) + 2 NaCl(aq)

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4 years ago
A common antacid contains the acid-neutralizing agent sodium hydrogen carbonate. Write the chemical formula for sodium hydrogen
kaheart [24]
Sodium hydrogen carbonate has:
sodium \:  ion ( {Na}^{+}), hydrogen \\  ion ( {H}^{+}), and \:  carbonate \\ ion ( {CO3}^{2-})
The + from Na+ and + from H+ makes 2+, and therefore the 2- from CO3 evens the charges to neutral.

Not to be confused with Sodium Carbonate, (Na2CO3), which lack an H, Sodium Hydrogen Carbonate is sometimes shortened to just Sodium Bicarbonate. It is used in the kitchen (cooking) as "baking soda."

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3 0
3 years ago
The painkiller, Advil® contains the active ingredient ibuprofen (IB), which has a pKb of
denis23 [38]

This problem is providing the basic dissociation constant of ibuprofen (IB) as 5.20, its pH as 8.20 and is requiring the equilibrium concentration of the aforementioned drug by giving the chemical equation at equilibrium it takes place. The obtained result turned out to be D) 4.0 × 10−7 M, according to the following work:

First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:

Kb=\frac{[IBH^+][OH^-]}{[IB]}

Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:

pOH=14-8.20=5.80

[OH^-]=10^{-5.8}=1.585x10^{-6}M

Kb=10^{-5.20}=6.31x10^{-6}

Then, since the concentration of these ions equal that of the conjugated acid of the ibuprofen (IBH⁺), we can plug in these and the Kb to obtain:

6.31x10^{-6}=\frac{(1.585x10^{-6})(1.585x10^{-6})}{[IB]}

Finally, we solve for the equilibrium concentration of ibuprofen:

[IB]=\frac{(1.585x10^{-6})(1.585x10^{-6})}{6.31x10^{-6}}=4.0x10^{-7}

Learn more:

(Weak base equilibrium calculation) brainly.com/question/9426156

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