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2 years ago

BRAINLIEST TO CORRECT ANSWER

Chemistry

1 answer:

rosijanka [135]2 years ago

7 0

Answer:

A right? I'm pretty sure it's A

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Need help please I need to select one element for each following families on the periodic table

max2010maxim [7]

Answer:

Semi Metals-Boron, Silicon

Noble Gasses-Helium, Argon

Halogens-Clorine, Iodine

Transition metals-Iron, Tungsten

Alkaline earth metals-Calcium, Magnesium

8 0

3 years ago

The irreversible elementary gas-phase reaction is carried out isothermally at 305 K in a packed-bed reactor with 100 kg of catal

tamaranim1 [39]

Answer:

0.856.

Explanation:

Lets represent the irreversible elementary gas phase equation of reaction as

A + B -----------------------------------> C + D

We have that the percentage of conversion is 80%.

The pressure, p from the ratio of exit pressure and entering pressure is p = 2/20 = 1/10 = 0.1.

Therefore, n = 1 - p^2/ weight of the catalyst = 1 - 0.1^2/ 100 = 9.9 × 10^-3 kg cat^-.

Now, let's make use of the equation below;

J/ 1 - J = kb^2/ u [ w - nw^2/2] ----------(1).

0.8 / 1- 0.8 = k ( 0.4)^2/ 10 [ 100 - (9.9× 10^-3 × 100^2/ 2] .

k = 4.95 dm^6/ kg.cat .mol.min

The turbulent flow= 1/2 × 9.9 × 10^-3 = 4.95 × 10^-3 kg cat^-.

Thus, making use of the equation (1) again, we have that;

{4.95 × 10^-3 × 0.4}/ 10 × [ 100 - (4.95 × 10^-3 × 100^2)] / 2 = 5.964.

Therefore, a/1 - a = 5.964.

5.964( 1 - a) = a.

5.964 - 5.964a = a.

5.964 = a + 5.964a.

5.964 = 6.964a.

a = 5.964/ 6.964 = 0.856.

5 0

2 years ago

When a solution of barium nitrate and a solution of copper (II) sulfate are mixed, a chemical reaction produces solid barium sul

Artemon [7]

The total mass of the products is 10.76 g + 204.44 g = 215.20 g.
The masses of all the reactants but one are known so,

215.20 g - 120.00 g - 8.15 g - 75.00 g = 12.05 g

12.05 g is the mass of the unweighed barium nitrate.

8 0

3 years ago

Read 2 more answers

How many grams of iron(III) oxide would be required to make 187 g of iron

enyata [817]

Answer:267 g

Explanation:

4 0

3 years ago

Calculate the density of chloroform

Rina8888 [55]

Answer: The density of chloroform is 1.47 g/mL

Explanation : Given,

Volume = 40.5 mL

Mass of cylinder = 85.16 g

Mass of cylinder and liquid = 145.10 g

First we have to calculate the mass of liquid (chloroform).

Mass of liquid = Mass of cylinder and liquid - Mass of cylinder

Mass of liquid = 145.10 g - 85.6 g

Mass of liquid = 59.5 g

Now we have to calculate the density of liquid (chloroform).

Formula used:

$Density=\frac{Mass}{Volume}$

Now putting g all the given values in this formula, we get:

$Density=\frac{59.5g}{40.5mL}$

$Density=1.47g/mL$

Therefore, the density of chloroform is 1.47 g/mL

5 0

2 years ago

BRAINLIEST TO CORRECT ANSWER ​

BRAINLIEST TO CORRECT ANSWER