Reactant C is the limiting reactant in this scenario.
Explanation:
The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.
Balanced chemical reaction is:
A + 2B + 3C → 2D + E
number of moles
A = 0.50 mole
B = 0.60 moles
C = 0.90 moles
Taking A as the reactant
1 mole of A reacted to form 2 moles of D
0.50 moles of A will produce 
= 
thus 0.50 moles of A will produce 1 mole of D
Taking B as the reactant
2 moles of B reacted to form 2 moles of D
0.60 moles of B reacted to form x moles of D
= 
x = 2 moles of D is produced.
Taking C as the reactant:
3 moles of C reacted to form 2 moles of D
O.9 moles of C reacted to form x moles of D
= 
= 0.60 moles of D is formed.
Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.
3.19 x 10³
Explanation:
The exponential format of the a figure is used to simplify the expression of big numbers to make them easier to work with.
The number is simply raised to the power of tens.
3,186
This is number three thousand one hundred and eighty six
The highest number here is a thousand
A thousand is 10³
So we simply take the rest of the values and express it this way;
3.186 x 10³ or 3.19 x 10³ on rounding up
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A. Can you help me with this
I. The diagonals of a square are perpendicular.
II. The diagonals of a rhombus are perpendicular.
III. The diagonals of a rectangle are perpendicular.
Which of the above statements are true?
A)I.II.III
B)None of the above statements are true.
C) only I
D)I.III
The following chemical reaction will occur:
Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)
Explanation:
Because the bromide (Br₂) have a higher reactivity than iodide (I₂) it is able the remove the iodide from its salts. So the bromide will react with sodium iodine (NaI) to produce sodium bromide (NaBr) and iodine.
The chemical reaction is:
Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)
where:
(l) - liquid
(s) - solid
Learn more about:
balancing chemical equations
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