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lutik1710 [3]
3 years ago
10

For the following reaction, identify the limiting reactant and calculate the grams of product produced when 25.0 grams of the fi

rst reactant and 40.0 grams of the second reactant are used: (3 pts)
2SO2 + O2 --> 2SO3

You will have two answers for this question –

Limiting reactant
amount of SO3 produced (grams)
Chemistry
1 answer:
Margaret [11]3 years ago
6 0

Answer:

The answer to your question is a) limiting reactant SO₂

                                                     b)mass of SO₃ produced 31.25 g

Explanation:

Data

mass of SO₂ = 25 g

mass of O₂ = 40 g

Balanced Reaction

                                     2SO₂   +   O₂   ⇒   2SO₃

Process

1.- Calculate the molecular mass of the reactants

SO₂ = 32 + (16 x 2) = 32 + 32 = 64

O₂ = 16 x 2 =32

2.- Use proportions to determine the limiting reactant

Theoretical proportion    2(SO₂) / O₂ = 2(64) / 32 = 4

Experimental proportion   SO₂ / O₂ = 25 / 40 = 0.625

From these results, we determined that the limiting reactant is SO₂, because the proportion in the experiment is lower.

3.- Amount of SO₃ produced

Mass of SO₃ = 32 + (3 x 16) = 80 g

                        128 g of SO₂   ---------------  2(80) g of SO₃

                        25 g of SO₂    ---------------   x

                         x = (25 x 2 x 80) / 128

                         x = 31.25 g of SO₃

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I'm stuck on this assignment, +20 PTS and BRAINLIEST for step by step:
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Answer:

2. 2.74 L

3. 488 K

4. 7.47 L

5. 38.6 L

6. 2.85 mol

7. 319 K

8. 3.43 kPa

Explanation:

Generally speaking, you want to convert units to SI units, but in this case, we are working with ratios.  This makes up for using the units that wouldn't appropriate elsewhere.

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4.  Do the same as above, but for V₂.  

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5.  Use the equation V₁/n₁ = V₂/n₂.  Solve for V₂.  

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6.  Do the same as above, but for n₂.

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7.  Use the equation P₁/T₁ = P₂/T₂.  Solve for T₂.  

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