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2 years ago

-7p^ 3(4p ^2 + 3p - 1)

Mathematics

2 answers:

Rom4ik [11]2 years ago

6 0

- 28 $p^{5}$ - 7 $p^{4}$ + 7p³

distributing and adding exponents of like terms gives

- 28 $p^{3+2}$ - 7 $p^{3+1}$ + 7p³

= - 28 $p^{5}$ - 7 $p^{4}$ + 7p³

nordsb [41]2 years ago

3 0

How do u do that ???

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Pq + 4; use p=4, and q = 4

dangina [55]

Answer:

Step-by-step explanation:

pq + 4

Given:

p = 4

q = 4

We plug the numbers in:

pq + 4

4(4) + 4

16 + 4

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3 years ago

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Hmm, I need someone to answer this. Just answer it right, if you don't know it then don't answer, It's annoying. It's probably r

Phoenix [80]

Answer:

Step-by-step explanation:

f(s)=2s+25 and s(w)=25w

f(w)=2(25w)+25

f(w)=50w+25

The ujits for the composite function are f=number of flowers and w=number of weeks.

f(30)=50(30)+25

f(30)=1500+25

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2 years ago

Evaluate 30 + a - y, let a = 6 and y = 5

yuradex [85]

30 + 6 -5=31
30 +a-y

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2 years ago

Liam sits on a merry-go-round at the local fair. He completes 12 revolutions in 4

Musya8 [376]

Answer:

1/3 min ( = 20 seconds)

Step-by-step explanation:

The period of the ride is the time he takes to complete 1 revolution

We are given:

12 revolutions -------> takes 4 min

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7 0

3 years ago

Can you guys pls help me with this math question

Sindrei [870]

Answer:

Dimensions: 150 m x 150 m

Area: 22,500m²

Step-by-step explanation:

Given information:

Rectangular field
Total amount of fencing = 600m
All 4 sides of the field need to be fenced

Let $x$ = width of the field

Let $y$ = length of the field

Create two equations from the given information:

Area of field: $A= xy$

Perimeter of fence: $2(x + y) = 600$

Rearrange the equation for the perimeter of the fence to make y the subject:

$\begin{aligned} \implies 2(x + y) & = 600\\ x+y & = 300\\y & = 300-x\end{aligned}$

Substitute this into the equation for Area:

$\begin{aligned}\implies A & = xy\\& = x(300-x)\\& = 300x-x^2 \end{aligned}$

To find the value of x that will make the area a maximum, differentiate A with respect to x:

$\begin{aligned}A & =300x-x^2\\\implies \dfrac{dA}{dx}& =300-2x\end{aligned}$

Set it to zero and solve for x:

$\begin{aligned}\dfrac{dA}{dx} & =0\\ \implies 300-2x & =0 \\ x & = 150 \end{aligned}$

Substitute the found value of x into the original equation for the perimeter and solve for y:

$\begin{aligned}2(x + y) & = 600\\\implies 2(150)+2y & = 600\\2y & = 300\\y & = 150\end{aligned}$

Therefore, the dimensions that will give Tanya the maximum area are:

150 m x 150 m

The maximum area is:

$\begin{aligned}\implies \sf Area_{max} & = xy\\& = 150 \cdot 150\\& = 22500\: \sf m^2 \end{aligned}$

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1 year ago