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Harrizon [31]
3 years ago
15

The major source of aluminum in the world this bauxite (mostly aluminum oxide). It’s thermal decomposition can be represented by

:
Al2 O3 (s) —> 2 Al (s) + 3/2 O2 (g)


ΔH rxn = 1676


If aluminum is produced this way, how many grams of aluminum can conform when 1.000×10^3 kJ of heat is transferred?
Chemistry
1 answer:
Artyom0805 [142]3 years ago
7 0

Answer:

The correct answer is 32.2 grams.

Explanation:

Based on the given information, the enthalpy of formation for aluminum oxide is 1676 kJ/mol. It signifies towards the energy that is required to generate aluminum and oxygen, and both of these exhibit zero enthalpy of formation. Therefore, the ΔHreaction is the required energy to generate 2 moles of aluminum. Thus, the energy needed for the formation of single mole of aluminum is,  

ΔHrxn = 1676/2 = 838 kJ/mol

Q or the energy input mentioned in the given case is 1000 kJ. Therefore, the number of moles of Al generated is,  

(1000 kJ) / (838 kJ/Al mole) = 1.19 moles of Aluminum

The grams of aluminum produced can be obtained by using the formula,  

mass = moles * molecular mass

= 1.19 * 26.98

= 32.2 grams.  

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2 AIPO4 + 3 BaCl2 --> 2 AICIz + 1 Baz(PO4)2
givi [52]

Answer:

12.3 moles of AlCl_{3} are produced by reacting 18.4 moles of BaCl_{2} .

Explanation:

Balanced reaction: 2AlPO_{4}+3BaCl_{2}\rightarrow 2AlCl_{3}+Ba_{3}(PO_{4})_{2}

According to balanced equation:

3 molecules of BaCl_{2} produce 2 molecules of AlCl_{3}

So 3N_{A} molecules of BaCl_{2} produce 2N_{A}  molecules of AlCl_{3} (N_{A} is avogadro number).

We know 1 mol of molecule = N_{A} number of molecules.

So 3 moles of BaCl_{2} produce 2 moles of AlCl_{3}.

Hence 18.4 moles of BaCl_{2} produce (\frac{2}{3}\times 18.4) moles of AlCl_{3} or 12.3 moles of AlCl_{3} .

3 0
4 years ago
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olya-2409 [2.1K]

Answer:

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Explanation:

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3 years ago
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Jobisdone [24]

Answer:

See explanation below

Explanation:

You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.

Now let's analyze what is happening in the reaction so we can predict the final product.

We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.

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Hope this helps

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