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Strike441 [17]
3 years ago
15

Donald has nine one-day passes to Dizzyworld. He can go alone and use one, or he can take a friend and use two. If he visits eve

ry day until he uses all the passes, in how many different ways can he use them? Using a two day for four days and then going alone at the end (2,2,2,2,1) is different from reversing the order (1,2,2,2,2).
I don't know the answer to this question.
Mathematics
2 answers:
Nata [24]3 years ago
8 0
There is 5 umbers in the sequence so the 1 can go in 5 different places
Mazyrski [523]3 years ago
7 0
(1,2,2,2,2),(2,1,2,2,2)
Observe, the 1 can go in 5 diff places
so 5 ways
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ale4655 [162]
We can split this up into 3 rectangles.  2 vertical ones (8 x 3) and one horizontal one in the middle (5 x (8 - 5)

8 x 3 = 24
24 x 2 = 48

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6 0
3 years ago
Bob can ride his bike 6.5 miles in 20 minutes what is the rate of speed in miles per hour
vladimir2022 [97]

Answer:

19.5 miles per hour

Step-by-step explanation:

We need to change 20 minutes to hours

1 hours = 60 minutes

20 minutes * 1 hour/60 minutes = 1/3 hour

To find miles per hour we take the miles and divide by hours

6.5 miles

---------------- = 19.5 miles per hour

1/3 hours

7 0
4 years ago
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How many elements must a set have if the number of proper subsets of the set is one half of the total number of subsets of the​
lora16 [44]
The set  X = { x , {x} }  would, I think,  fit the Bill
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6 0
3 years ago
Find the derivative of the following. please show the steps when you answer :1) f(x) = 8xe^x2) y= 5xe^x^43) f(x)= x^8+5/x4) f(t)
borishaifa [10]

Answer:

Since,

\frac{d}{dx}x^n = nx^{n-1}

\frac{d}{dx}(f(x).g(x)) = f(x).\frac{d}{dx}(g(x)) + g(x).\frac{d}{dx}(f(x))

\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x).f'(x) - f(x) g'(x)}{(g(x))^2}

1) y = 8x e^x

Differentiating with respect to x,

\frac{dy}{dx}=8( x \times e^x + e^x) = 8(xe^x + e^x) = 8e^x(x+1)

2) y = 5x e^{x^4}

Differentiating w. r. t x,

\frac{dy}{dx}=5(x\times 4x^3 e^{x^4}+e^{x^4})=5e^{x^4}(4x^4+1)

3) y = x^8 + \frac{5}{x^4}

Differentiating w. r. t. x,

\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}

4) f(t) = te^{11}-6t^5

Differentiating w. r. t. t,

f'(t) = e^{11} - 30t^4

5) g(p) = p\ln(2p+3)

Differentiating w. r. t. p,

g'(p) = p\frac{1}{2p+3}(2) + \ln(2p+3) = \frac{2p}{2p+3}+\ln(2p+3)

6) z = (te^{6t}+e^{5t})^7

Differentiating w. r. t. t,

\frac{dz}{dt}=7(te^{6t}+e^{5t})^6 ( 6te^{6t}+e^{6t} + 5e^{5t})

7) w =\frac{2y + y^2}{7+y}

Differentiating w. r. t. y,

\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}

7 0
3 years ago
PLEASE HELP!!
Andre45 [30]

Answer:

I think the answer is c

Step-by-step explanation:

Because it says at most? am I right

8 0
3 years ago
Read 2 more answers
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